To find the experimental probability that a 10th-grade student chosen at random has at least one, but no more than two, siblings, we need to perform the following steps:
1. Identify and Sum Up the Total Number of Students Surveyed:
The numbers of students with 0, 1, 2, and 3 siblings are given in the table:
- Students with 0 siblings: 4
- Students with 1 sibling: 18
- Students with 2 siblings: 10
- Students with 3 siblings: 8
Summing these values, we get the total number of students surveyed:
[tex]\[
4 + 18 + 10 + 8 = 40
\][/tex]
2. Determine the Number of Students with 1 or 2 Siblings:
The numbers of students with 1 and 2 siblings are:
- Students with 1 sibling: 18
- Students with 2 siblings: 10
Summing these values, we get the number of students with 1 or 2 siblings:
[tex]\[
18 + 10 = 28
\][/tex]
3. Calculate the Experimental Probability:
The experimental probability is the ratio of the number of students with 1 or 2 siblings to the total number of students, multiplied by 100 to get a percentage:
[tex]\[
\left( \frac{28}{40} \right) \times 100 = 70.0\%
\][/tex]
4. Round to the Nearest Whole Percent:
We already have a calculation of 70.0%, and this rounded to the nearest whole percent remains 70%.
Therefore, the experimental probability that a 10th-grade student chosen at random has at least one but no more than two siblings, rounded to the nearest whole percent, is [tex]\(\boxed{70\%}\)[/tex].
