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To determine the moles of each substance given their respective masses and molar masses, follow these steps:
1. Molar masses:
- The molar mass of copper (Cu) is [tex]\( 63.55 \, \text{g/mol} \)[/tex].
- The molar mass of sulfur (S) is [tex]\( 32.07 \, \text{g/mol} \)[/tex].
2. Calculate the number of moles of copper:
- Given mass of copper: [tex]\( 40.2 \, \text{g} \)[/tex].
- The formula to calculate moles is:
[tex]\[ \text{moles of Cu} = \frac{\text{mass of Cu}}{\text{molar mass of Cu}} \][/tex]
- Substituting the values:
[tex]\[ \text{moles of Cu} = \frac{40.2 \, \text{g}}{63.55 \, \text{g/mol}} \approx 0.632 \, \text{moles Cu} \][/tex]
3. Calculate the number of moles of sulfur:
- Given mass of sulfur: [tex]\( 14.1 \, \text{g} \)[/tex].
- The formula to calculate moles is:
[tex]\[ \text{moles of S} = \frac{\text{mass of S}}{\text{molar mass of S}} \][/tex]
- Substituting the values:
[tex]\[ \text{moles of S} = \frac{14.1 \, \text{g}}{32.07 \, \text{g/mol}} \approx 0.440 \, \text{moles S} \][/tex]
To summarize:
- There are approximately [tex]\( 0.632 \, \text{moles Cu} \)[/tex] in [tex]\( 40.2 \, \text{g} \)[/tex] of copper.
- There are approximately [tex]\( 0.440 \, \text{moles S} \)[/tex] in [tex]\( 14.1 \, \text{g} \)[/tex] of sulfur.
These values will be used to determine the limiting and excess reactants in the reaction.
1. Molar masses:
- The molar mass of copper (Cu) is [tex]\( 63.55 \, \text{g/mol} \)[/tex].
- The molar mass of sulfur (S) is [tex]\( 32.07 \, \text{g/mol} \)[/tex].
2. Calculate the number of moles of copper:
- Given mass of copper: [tex]\( 40.2 \, \text{g} \)[/tex].
- The formula to calculate moles is:
[tex]\[ \text{moles of Cu} = \frac{\text{mass of Cu}}{\text{molar mass of Cu}} \][/tex]
- Substituting the values:
[tex]\[ \text{moles of Cu} = \frac{40.2 \, \text{g}}{63.55 \, \text{g/mol}} \approx 0.632 \, \text{moles Cu} \][/tex]
3. Calculate the number of moles of sulfur:
- Given mass of sulfur: [tex]\( 14.1 \, \text{g} \)[/tex].
- The formula to calculate moles is:
[tex]\[ \text{moles of S} = \frac{\text{mass of S}}{\text{molar mass of S}} \][/tex]
- Substituting the values:
[tex]\[ \text{moles of S} = \frac{14.1 \, \text{g}}{32.07 \, \text{g/mol}} \approx 0.440 \, \text{moles S} \][/tex]
To summarize:
- There are approximately [tex]\( 0.632 \, \text{moles Cu} \)[/tex] in [tex]\( 40.2 \, \text{g} \)[/tex] of copper.
- There are approximately [tex]\( 0.440 \, \text{moles S} \)[/tex] in [tex]\( 14.1 \, \text{g} \)[/tex] of sulfur.
These values will be used to determine the limiting and excess reactants in the reaction.
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