Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
To determine the correct grouping that allows us to factor the quadratic expression [tex]\( 6x^2 + 7x - 5 \)[/tex], we need to find the correct pair of middle terms that sum to [tex]\( 7x \)[/tex] and whose product equals the product of the coefficient of [tex]\( x^2 \)[/tex] and the constant term. In this case, the coefficient of [tex]\( x^2 \)[/tex] is [tex]\( 6 \)[/tex], and the constant term is [tex]\(-5\)[/tex]. Therefore, the correct middle terms should come from pairs of terms that multiply to [tex]\( 6 \times (-5) = -30 \)[/tex] and sum to [tex]\( 7x \)[/tex].
Let's evaluate each option step-by-step:
### Option 1: [tex]\( 6x^2 - 4x + 11x - 5 \)[/tex]
- Sum of middle terms:
[tex]\[ -4x + 11x = 7x \][/tex]
- Product of middle terms:
[tex]\[ (-4) \times 11 = -44 \quad (\text{not equal to } -30) \][/tex]
This option does not work.
### Option 2: [tex]\( 6x^2 - 2x + 9x - 5 \)[/tex]
- Sum of middle terms:
[tex]\[ -2x + 9x = 7x \][/tex]
- Product of middle terms:
[tex]\[ (-2) \times 9 = -18 \quad (\text{not equal to } -30) \][/tex]
This option does not work.
### Option 3: [tex]\( 6x^2 - 6x + 9x - 9 \)[/tex]
- Sum of middle terms:
[tex]\[ -6x + 9x = 3x \quad (\text{not equal to } 7x) \][/tex]
This option does not work.
### Option 4: [tex]\( 6x^2 - 3x + 10x - 5 \)[/tex]
- Sum of middle terms:
[tex]\[ -3x + 10x = 7x \][/tex]
- Product of middle terms:
[tex]\[ (-3) \times 10 = -30 \quad (\text{equal to } -30) \][/tex]
This option works because both the sum and product conditions are satisfied.
Thus, the correct grouping of the quadratic [tex]\( 6x^2 + 7x - 5 \)[/tex] is given by:
[tex]\[ 6x^2 - 3x + 10x - 5 \][/tex]
The correct answer is:
[tex]\[ \boxed{6x^2 - 3x + 10x - 5} \][/tex]
Let's evaluate each option step-by-step:
### Option 1: [tex]\( 6x^2 - 4x + 11x - 5 \)[/tex]
- Sum of middle terms:
[tex]\[ -4x + 11x = 7x \][/tex]
- Product of middle terms:
[tex]\[ (-4) \times 11 = -44 \quad (\text{not equal to } -30) \][/tex]
This option does not work.
### Option 2: [tex]\( 6x^2 - 2x + 9x - 5 \)[/tex]
- Sum of middle terms:
[tex]\[ -2x + 9x = 7x \][/tex]
- Product of middle terms:
[tex]\[ (-2) \times 9 = -18 \quad (\text{not equal to } -30) \][/tex]
This option does not work.
### Option 3: [tex]\( 6x^2 - 6x + 9x - 9 \)[/tex]
- Sum of middle terms:
[tex]\[ -6x + 9x = 3x \quad (\text{not equal to } 7x) \][/tex]
This option does not work.
### Option 4: [tex]\( 6x^2 - 3x + 10x - 5 \)[/tex]
- Sum of middle terms:
[tex]\[ -3x + 10x = 7x \][/tex]
- Product of middle terms:
[tex]\[ (-3) \times 10 = -30 \quad (\text{equal to } -30) \][/tex]
This option works because both the sum and product conditions are satisfied.
Thus, the correct grouping of the quadratic [tex]\( 6x^2 + 7x - 5 \)[/tex] is given by:
[tex]\[ 6x^2 - 3x + 10x - 5 \][/tex]
The correct answer is:
[tex]\[ \boxed{6x^2 - 3x + 10x - 5} \][/tex]
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.