Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

The function [tex]\( h(a) = \sqrt{a^2 + 25} \)[/tex] can be used to find the length of the hypotenuse of a right triangle with one leg length of 5 inches and the other leg length [tex]\( a \)[/tex].

What is the length of the hypotenuse of a right triangle with leg lengths of 5 inches and 12 inches?

A. 7 inches
B. 13 inches
C. 17 inches
D. 60 inches


Sagot :

To solve for the length of the hypotenuse of a right triangle with leg lengths of 5 inches and 12 inches, we can use the Pythagorean theorem. This theorem states that for a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b). The formula is:

[tex]\[ c^2 = a^2 + b^2 \][/tex]

In this problem, one leg (a) is given as 12 inches and the other leg (b) is 5 inches. We'll substitute these values into the Pythagorean theorem and solve for c, the hypotenuse.

1. First, square both leg lengths:

[tex]\[ 12^2 = 144 \][/tex]
[tex]\[ 5^2 = 25 \][/tex]

2. Add these squared values together:

[tex]\[ 144 + 25 = 169 \][/tex]

3. Take the square root of the result to find the length of the hypotenuse:

[tex]\[ c = \sqrt{169} \][/tex]

[tex]\[ c = 13 \][/tex]

Thus, the length of the hypotenuse of the right triangle with leg lengths of 5 inches and 12 inches is 13 inches.

So, the correct answer is:
13 inches.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.