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Divide the following complex numbers and express the result in standard form [tex]\(a + bi\)[/tex], where [tex]\(a\)[/tex] and [tex]\(b\)[/tex] are fractions in lowest terms:

[tex]\[
\frac{1+2i}{5+4i}
\][/tex]

Sagot :

To divide the complex numbers [tex]\(\frac{1+2i}{5+4i}\)[/tex], we need to express the result in the standard form [tex]\(a + bi\)[/tex], where [tex]\(a\)[/tex] and [tex]\(b\)[/tex] are real numbers.

### Step-by-Step Solution:

1. Conjugate of the Denominator:
The first step in dividing complex numbers is to multiply both the numerator and the denominator by the conjugate of the denominator. The conjugate of [tex]\(5 + 4i\)[/tex] is [tex]\(5 - 4i\)[/tex].

[tex]\[ \frac{1+2i}{5+4i} \times \frac{5-4i}{5-4i} = \frac{(1+2i)(5-4i)}{(5+4i)(5-4i)} \][/tex]

2. Multiply the Numerator:
We distribute the terms in the numerator:

[tex]\[ (1+2i)(5-4i) = 1 \cdot 5 + 1 \cdot (-4i) + 2i \cdot 5 + 2i \cdot (-4i) \][/tex]

Simplify each term:

[tex]\[ = 5 - 4i + 10i - 8i^2 \][/tex]

Since [tex]\(i^2 = -1\)[/tex], replace [tex]\(i^2\)[/tex] with [tex]\(-1\)[/tex]:

[tex]\[ = 5 - 4i + 10i + 8 = 13 + 6i \][/tex]

3. Multiply the Denominator:
To simplify the denominator, recognize that we are multiplying a complex number by its conjugate, which results in the sum of the squares of the real and imaginary parts:

[tex]\[ (5+4i)(5-4i) = 5^2 - (4i)^2 \][/tex]

Since [tex]\(i^2 = -1\)[/tex], this becomes:

[tex]\[ = 25 - 16(-1) = 25 + 16 = 41 \][/tex]

4. Combine the Results:
Now, we have:

[tex]\[ \frac{13 + 6i}{41} \][/tex]

We can separate this into real and imaginary parts:

[tex]\[ = \frac{13}{41} + \frac{6}{41}i \][/tex]

### Final Answer:
Thus, the result in standard form is:

[tex]\[ \frac{1+2i}{5+4i} = \frac{13}{41} + \frac{6}{41}i \][/tex]

In decimal form, the result simplifies to approximately:

[tex]\[ 0.3170731707317074 + 0.14634146341463417i \][/tex]

This is the final simplified form of the division of complex numbers [tex]\( \frac{1+2i}{5+4i} \)[/tex].