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QUESTIONS:

1) Steel bolts from supplier A are nominally 45 mm in length. A sample of these bolts was measured, and the frequency data recorded is shown below:

\begin{tabular}{|l|l|}
\hline Length (mm) & Frequency \\
\hline 44.4 & 1 \\
\hline 44.7 & 14 \\
\hline 45.0 & 15 \\
\hline 45.1 & 17 \\
\hline 45.2 & 13 \\
\hline 45.5 & 13 \\
\hline 45.8 & 2 \\
\hline
\end{tabular}

Table Q1a


Sagot :

To find the mean length of the steel bolts from supplier [tex]\( A \)[/tex], we need to perform a series of calculations. Here is the detailed, step-by-step solution:

1. List of Bolt Lengths and Frequencies:

The data from Table Q1a shows:
[tex]\[ \begin{array}{|c|c|} \hline \text{Length (mm)} & \text{Frequency} \\ \hline 44.4 & 1 \\ \hline 44.7 & 14 \\ \hline 45.0 & 15 \\ \hline 45.1 & 17 \\ \hline 45.2 & 13 \\ \hline 45.5 & 13 \\ \hline 45.8 & 2 \\ \hline \end{array} \][/tex]

2. Total Number of Bolts:

We sum up the frequencies to find the total number of bolts:
[tex]\[ 1 + 14 + 15 + 17 + 13 + 13 + 2 = 75 \][/tex]
There are 75 bolts in total.

3. Mean Length Calculation:

To calculate the mean length, we need to take into account the frequency of each length:

First, multiply each length by its corresponding frequency:
[tex]\[ \begin{align*} 44.4 \times 1 &= 44.4 \\ 44.7 \times 14 &= 625.8 \\ 45.0 \times 15 &= 675.0 \\ 45.1 \times 17 &= 766.7 \\ 45.2 \times 13 &= 587.6 \\ 45.5 \times 13 &= 591.5 \\ 45.8 \times 2 &= 91.6 \\ \end{align*} \][/tex]

4. Sum of All Lengths (Weighted by Frequency):

Add up all these products:
[tex]\[ 44.4 + 625.8 + 675.0 + 766.7 + 587.6 + 591.5 + 91.6 = 3382.6 \][/tex]

5. Mean Length:

Finally, divide the total sum of the lengths by the total number of bolts to get the mean length:
[tex]\[ \text{Mean length} = \frac{3382.6}{75} \approx 45.10133333333333 \][/tex]

So, the mean length of the steel bolts from supplier [tex]\( A \)[/tex] is approximately [tex]\( 45.101 \)[/tex] mm.
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