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Now change matrix [tex]\( B \)[/tex] to a [tex]\( 3 \times 3 \)[/tex] matrix and enter these values for [tex]\( B \)[/tex]:

[tex]\[
B = \begin{bmatrix}
1.2 & 1.4 & 3.1 \\
2.2 & 1.1 & 5.6 \\
3.7 & 4.2 & 6.7
\end{bmatrix}
\][/tex]

Then select [tex]\( A \cdot B \)[/tex] to calculate the product:

[tex]\[ c_{11} = \square \quad 56.1 \checkmark \quad c_{12} = 12.1 \square \checkmark \quad c_{13} = \square \][/tex]

Last calculation:

[tex]\[ 3\begin{bmatrix} 3 \\ 19 \\ 12 \end{bmatrix} \begin{bmatrix} -1 & -3 & -5 \end{bmatrix} = \begin{bmatrix} d_{11} & d_{12} & d_{13} \\ d_{21} & d_{22} & d_{23} \\ -36 & -108 & -180 \end{bmatrix} \][/tex]

[tex]\[ d_{11} = \square \][/tex]
[tex]\[ d_{12} = \square \][/tex]
[tex]\[ d_{13} = \square \][/tex]
[tex]\[ d_{21} = \square \][/tex]
[tex]\[ d_{22} = \square \][/tex]
[tex]\[ d_{23} = \square \][/tex]


Sagot :

Let's begin with the step-by-step calculation of the given tasks:

### 1. Calculation of [tex]\( A \cdot B \)[/tex]

Given matrices:

[tex]\[ A = \begin{pmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9 \end{pmatrix}, \quad B = \begin{pmatrix} 1.2 & 1.4 & 3.1 \\ 2.2 & 1.1 & 5.6 \\ 3.7 & 4.2 & 6.7 \end{pmatrix} \][/tex]

Compute the product [tex]\( A \cdot B \)[/tex]:

[tex]\[ \begin{pmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9 \end{pmatrix} \cdot \begin{pmatrix} 1.2 & 1.4 & 3.1 \\ 2.2 & 1.1 & 5.6 \\ 3.7 & 4.2 & 6.7 \end{pmatrix} = \begin{pmatrix} c_{11} & c_{12} & c_{13} \\ ... & ... & ... \\ ... & ... & ... \end{pmatrix} \][/tex]

Using the true results:

[tex]\[ c_{11} = 16.7, \quad c_{12} = 16.2, \quad c_{13} = 34.4 \][/tex]

So we can fill in the appropriate checkmarks:

[tex]\[ c_{11} = 16.7 \checkmark, \quad c_{12} = 16.2 \checkmark, \quad c_{13} = 34.4 \checkmark \][/tex]

### 2. Final Calculation with vector and row vector

Given:

[tex]\[ 3 \begin{pmatrix} 3 \\ 19 \\ 12 \end{pmatrix} \begin{pmatrix} -1 & -3 & -5 \end{pmatrix} = \begin{pmatrix} d_{11} & d_{12} & d_{13} \\ d_{21} & d_{22} & d_{23} \\ -36 & -108 & -180 \end{pmatrix} \][/tex]

Computation for elements:

First, compute the product:

[tex]\[ \begin{pmatrix} 3 \\ 19 \\ 12 \end{pmatrix} \begin{pmatrix} -1 & -3 & -5 \end{pmatrix} = \begin{pmatrix} -3 & -9 & -15 \\ -19 & -57 & -95 \\ -12 & -36 & -60 \end{pmatrix} \][/tex]

Multiply by 3:

[tex]\[ 3 \cdot \begin{pmatrix} -3 & -9 & -15 \\ -19 & -57 & -95 \\ -12 & -36 & -60 \end{pmatrix} = \begin{pmatrix} d_{11} & d_{12} & d_{13} \\ d_{21} & d_{22} & d_{23} \\ -36 & -108 & -180 \end{pmatrix} \][/tex]

Thus,

[tex]\[ 3 \cdot \begin{pmatrix} -3 & -9 & -15 \\ -19 & -57 & -95 \\ -12 & -36 & -60 \end{pmatrix} = \begin{pmatrix} -9 & -27 & -45 \\ -57 & -171 & -285 \\ -36 & -108 & -180 \end{pmatrix} \][/tex]

So, fill in:

[tex]\[ d_{11} = -9 \checkmark, \quad d_{12} = -27 \checkmark, \quad d_{13} = -45 \checkmark \][/tex]
[tex]\[ d_{21} = -57 \checkmark, \quad d_{22} = -171 \checkmark, \quad d_{23} = -285 \checkmark \][/tex]

This completes the detailed step-by-step solution.