At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
To calculate the average velocity of the car, we need to follow these steps for each segment of the journey:
1. Calculate the average time for each segment:
First, for the distance of [tex]\(0.25 \, m\)[/tex]:
- Trial 1: [tex]\(2.24 \, s\)[/tex]
- Trial 2: [tex]\(2.21 \, s\)[/tex]
- Trial 3: [tex]\(2.23 \, s\)[/tex]
To find the average time, sum the times and divide by the number of trials:
[tex]\[ \text{Average time for first } 0.25 \, m = \frac{2.24 + 2.21 + 2.23}{3} = 2.2266666666666666 \, s \][/tex]
Next, for the distance from [tex]\(0.25 \, m\)[/tex] to [tex]\(0.50 \, m\)[/tex] (i.e., the second [tex]\(0.25 \, m\)[/tex]):
- Trial 1: [tex]\(3.16 \, s\)[/tex]
- Trial 2: [tex]\(3.08 \, s\)[/tex]
- Trial 3: [tex]\(3.15 \, s\)[/tex]
To find the average time, sum the times and divide by the number of trials:
[tex]\[ \text{Average time for second } 0.25 \, m = \frac{3.16 + 3.08 + 3.15}{3} = 3.1300000000000003 \, s \][/tex]
2. Calculate the average velocity for each segment:
The formula for average velocity is given by:
[tex]\[ \text{Average velocity} = \frac{\text{distance}}{\text{time}} \][/tex]
For the first [tex]\(0.25 \, m\)[/tex]:
[tex]\[ \text{Average velocity for first } 0.25 \, m = \frac{0.25 \, m}{2.2266666666666666 \, s} = 0.11227544910179642 \, m/s \][/tex]
For the second [tex]\(0.25 \, m\)[/tex]:
[tex]\[ \text{Average velocity for second } 0.25 \, m = \frac{0.25 \, m}{3.1300000000000003 \, s} = 0.07987220447284345 \, m/s \][/tex]
3. Provide the final answers:
- The average velocity of the car over the first [tex]\(0.25 \, m\)[/tex] is [tex]\(0.112 \, m/s\)[/tex] (rounded to three decimal places).
- The average velocity of the car over the second [tex]\(0.25 \, m\)[/tex] is [tex]\(0.080 \, m/s\)[/tex] (rounded to three decimal places).
1. Calculate the average time for each segment:
First, for the distance of [tex]\(0.25 \, m\)[/tex]:
- Trial 1: [tex]\(2.24 \, s\)[/tex]
- Trial 2: [tex]\(2.21 \, s\)[/tex]
- Trial 3: [tex]\(2.23 \, s\)[/tex]
To find the average time, sum the times and divide by the number of trials:
[tex]\[ \text{Average time for first } 0.25 \, m = \frac{2.24 + 2.21 + 2.23}{3} = 2.2266666666666666 \, s \][/tex]
Next, for the distance from [tex]\(0.25 \, m\)[/tex] to [tex]\(0.50 \, m\)[/tex] (i.e., the second [tex]\(0.25 \, m\)[/tex]):
- Trial 1: [tex]\(3.16 \, s\)[/tex]
- Trial 2: [tex]\(3.08 \, s\)[/tex]
- Trial 3: [tex]\(3.15 \, s\)[/tex]
To find the average time, sum the times and divide by the number of trials:
[tex]\[ \text{Average time for second } 0.25 \, m = \frac{3.16 + 3.08 + 3.15}{3} = 3.1300000000000003 \, s \][/tex]
2. Calculate the average velocity for each segment:
The formula for average velocity is given by:
[tex]\[ \text{Average velocity} = \frac{\text{distance}}{\text{time}} \][/tex]
For the first [tex]\(0.25 \, m\)[/tex]:
[tex]\[ \text{Average velocity for first } 0.25 \, m = \frac{0.25 \, m}{2.2266666666666666 \, s} = 0.11227544910179642 \, m/s \][/tex]
For the second [tex]\(0.25 \, m\)[/tex]:
[tex]\[ \text{Average velocity for second } 0.25 \, m = \frac{0.25 \, m}{3.1300000000000003 \, s} = 0.07987220447284345 \, m/s \][/tex]
3. Provide the final answers:
- The average velocity of the car over the first [tex]\(0.25 \, m\)[/tex] is [tex]\(0.112 \, m/s\)[/tex] (rounded to three decimal places).
- The average velocity of the car over the second [tex]\(0.25 \, m\)[/tex] is [tex]\(0.080 \, m/s\)[/tex] (rounded to three decimal places).
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.