To determine which of the given compounds is inorganic, let's analyze each option, identifying whether they are organic or inorganic compounds.
A. [tex]$C_6H_{12}O_6$[/tex]:
- This compound is glucose, a type of sugar. Sugars are organic compounds because they contain carbon-hydrogen (C-H) bonds. Hence, [tex]$C_6H_{12}O_6$[/tex] is an organic compound.
B. [tex]$KH_2PO_4$[/tex]:
- This is potassium dihydrogen phosphate. Inorganic compounds typically do not contain carbon-hydrogen (C-H) bonds. Potassium dihydrogen phosphate is composed of elements potassium (K), hydrogen (H), phosphorus (P), and oxygen (O) but lacks C-H bonds. Therefore, [tex]$KH_2PO_4$[/tex] is an inorganic compound.
C. [tex]$CH_3COOH$[/tex]:
- This compound is acetic acid, an organic compound. It contains carbon-hydrogen (C-H) bonds and is part of the carboxylic acid family. Thus, [tex]$CH_3COOH$[/tex] is an organic compound.
D. [tex]$C_2H_6$[/tex]:
- This compound is ethane, a simple hydrocarbon. Hydrocarbons are organic compounds as they contain carbon-hydrogen (C-H) bonds. Therefore, [tex]$C_2H_6$[/tex] is an organic compound.
E. [tex]$C_2H_5OH$[/tex]:
- This compound is ethanol, an alcohol. Alcohols are organic compounds due to the presence of carbon-hydrogen (C-H) bonds. Therefore, [tex]$C_2H_5OH$[/tex] is an organic compound.
Based on the above analysis, option B, [tex]$KH_2PO_4$[/tex] (potassium dihydrogen phosphate), is the only inorganic compound among the given options.
Therefore, the correct answer is:
B. [tex]$KH_2PO_4$[/tex]
