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Evaluate [tex]\( j(x) = \sqrt{3x + 1} \)[/tex] at [tex]\( x = 8 \)[/tex].

Sagot :

GinnyAnswer
To solve for [tex]\( j(8) \)[/tex] in the function [tex]\( j(x) = \sqrt{3x + 1} \)[/tex], follow these steps:

1. Identify the function:
The function given is [tex]\( j(x) = \sqrt{3x + 1} \)[/tex].

2. Substitute [tex]\( x \)[/tex] with 8:
We need to find the value of the function when [tex]\( x = 8 \)[/tex]. Thus, substitute 8 for [tex]\( x \)[/tex] in the function:
[tex]\[ j(8) = \sqrt{3(8) + 1} \][/tex]

3. Simplify inside the square root:
Calculate the expression inside the square root:
[tex]\[ 3(8) + 1 = 24 + 1 = 25 \][/tex]

4. Compute the square root:
Now, find the square root of 25:
[tex]\[ \sqrt{25} = 5 \][/tex]

Thus, the value of [tex]\( j(8) \)[/tex] is [tex]\( \boxed{5} \)[/tex].
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