Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
To factor the polynomial [tex]\( x^3 + 8x^2 + 15x \)[/tex] completely, follow these detailed steps:
### Step 1: Identify and Factor Out the Greatest Common Factor (GCF)
First, observe that each term in the polynomial [tex]\( x^3 + 8x^2 + 15x \)[/tex] contains the variable [tex]\( x \)[/tex]. Therefore, the greatest common factor (GCF) of these terms is [tex]\( x \)[/tex].
Factor out the GCF ([tex]\( x \)[/tex]) from each term:
[tex]\[ x^3 + 8x^2 + 15x = x(x^2 + 8x + 15) \][/tex]
### Step 2: Factor the Quadratic Expression Inside the Parenthesis
Next, focus on factoring the quadratic expression inside the parenthesis: [tex]\( x^2 + 8x + 15 \)[/tex].
To factor [tex]\( x^2 + 8x + 15 \)[/tex], we need to find two numbers that:
1. Multiply to the constant term, 15.
2. Add up to the coefficient of the middle term, 8.
The pairs of factors of 15 are:
- [tex]\( 1 \times 15 \)[/tex]
- [tex]\( 3 \times 5 \)[/tex]
Among these pairs, the numbers 3 and 5 add up to 8.
So, we can write the quadratic expression as the product of two binomials:
[tex]\[ x^2 + 8x + 15 = (x + 3)(x + 5) \][/tex]
### Step 3: Combine the Factorizations
Now, combine the GCF with the factored form of the quadratic expression:
[tex]\[ x(x^2 + 8x + 15) = x(x + 3)(x + 5) \][/tex]
### Conclusion
The completely factored form of the polynomial [tex]\( x^3 + 8x^2 + 15x \)[/tex] is:
[tex]\[ \boxed{x(x + 3)(x + 5)} \][/tex]
### Step 1: Identify and Factor Out the Greatest Common Factor (GCF)
First, observe that each term in the polynomial [tex]\( x^3 + 8x^2 + 15x \)[/tex] contains the variable [tex]\( x \)[/tex]. Therefore, the greatest common factor (GCF) of these terms is [tex]\( x \)[/tex].
Factor out the GCF ([tex]\( x \)[/tex]) from each term:
[tex]\[ x^3 + 8x^2 + 15x = x(x^2 + 8x + 15) \][/tex]
### Step 2: Factor the Quadratic Expression Inside the Parenthesis
Next, focus on factoring the quadratic expression inside the parenthesis: [tex]\( x^2 + 8x + 15 \)[/tex].
To factor [tex]\( x^2 + 8x + 15 \)[/tex], we need to find two numbers that:
1. Multiply to the constant term, 15.
2. Add up to the coefficient of the middle term, 8.
The pairs of factors of 15 are:
- [tex]\( 1 \times 15 \)[/tex]
- [tex]\( 3 \times 5 \)[/tex]
Among these pairs, the numbers 3 and 5 add up to 8.
So, we can write the quadratic expression as the product of two binomials:
[tex]\[ x^2 + 8x + 15 = (x + 3)(x + 5) \][/tex]
### Step 3: Combine the Factorizations
Now, combine the GCF with the factored form of the quadratic expression:
[tex]\[ x(x^2 + 8x + 15) = x(x + 3)(x + 5) \][/tex]
### Conclusion
The completely factored form of the polynomial [tex]\( x^3 + 8x^2 + 15x \)[/tex] is:
[tex]\[ \boxed{x(x + 3)(x + 5)} \][/tex]
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.