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What common base can be used to rewrite each side of the equation [tex]\(2^{x+3}-3=5\)[/tex]?

A. 2
B. 3
C. 5
D. 8

Sagot :

To determine the common base that can be used to rewrite each side of the equation [tex]\(2^{x+3} - 3 = 5\)[/tex], follow these steps:

1. Isolate the exponential term:

Start by isolating [tex]\(2^{x+3}\)[/tex]. Add 3 to both sides of the equation:
[tex]\[ 2^{x+3} - 3 + 3 = 5 + 3 \][/tex]
This simplifies to:
[tex]\[ 2^{x+3} = 8 \][/tex]

2. Express 8 as a power of 2:

Notice that 8 can be written as [tex]\(2^3\)[/tex]. This is because:
[tex]\[ 8 = 2^3 \][/tex]

3. Rewrite the equation with a common base:

Now that we know [tex]\(8\)[/tex] is [tex]\(2^3\)[/tex], we can rewrite the equation [tex]\(2^{x+3} = 8\)[/tex] using the common base [tex]\(2\)[/tex]:
[tex]\[ 2^{x+3} = 2^3 \][/tex]

4. Simplify the exponents:

Since the bases are the same, we can set the exponents equal to each other:
[tex]\[ x + 3 = 3 \][/tex]

5. Solve for [tex]\(x\)[/tex]:

Subtract 3 from both sides to isolate [tex]\(x\)[/tex]:
[tex]\[ x = 3 - 3 \][/tex]
[tex]\[ x = 0 \][/tex]

The common base that we used to rewrite each side of the equation is:
[tex]\[ \boxed{2} \][/tex]

This ensures the equation holds true when solved in terms of exponential form.