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What is the justification for step 3 in solving the equation?

[tex]\[
\frac{5}{2} h - \frac{15}{2} = \frac{1}{5} h
\][/tex]

Step 1: [tex]\(\frac{23}{10} h - \frac{15}{2} = 0\)[/tex]

Step 2: [tex]\(\frac{23}{10} h = \frac{15}{2}\)[/tex]

Step 3: [tex]\(h = \frac{75}{23}\)[/tex]

A. The subtraction property of equality
B. The addition property of equality
C. Combining like terms
D. The multiplication property of equality


Sagot :

Let's review the equation and the steps taken to solve it to understand the justification for Step 3 in the solution of the given equation:

Given:
[tex]\[ \frac{5}{2} h - \frac{15}{2} = \frac{1}{5} h \][/tex]

Here are the steps:

1. [tex]\[ \frac{23}{10} h - \frac{15}{2} = 0 \][/tex]

2. [tex]\[ \frac{23}{10} h = \frac{15}{2} \][/tex]

3. [tex]\[ h = \frac{75}{23} \][/tex]

To determine the justification for Step 3, we need to understand how we arrived at that specific step. In Step 2, we have:

[tex]\[ \frac{23}{10} h = \frac{15}{2} \][/tex]

To isolate [tex]\( h \)[/tex], we must divide both sides of the equation by [tex]\( \frac{23}{10} \)[/tex]. Dividing by a fraction is equivalent to multiplying by its reciprocal:

[tex]\[ h = \frac{\frac{15}{2}}{\frac{23}{10}} = \frac{15}{2} \times \frac{10}{23} = \frac{150}{46} = \frac{75}{23} \][/tex]

This action of dividing both sides by the coefficient of [tex]\( h \)[/tex] (which is [tex]\( \frac{23}{10} \)[/tex]) is consistent with the multiplication property of equality.

Hence, the correct justification for Step 3 is:

the multiplication property of equality.
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