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Find the product:
[tex]\[
(x+3)(x-7) = \,?
\][/tex]


Sagot :

Sure, let's find the product of the two binomials [tex]\( (x + 3) \)[/tex] and [tex]\( (x - 7) \)[/tex].

1. Distribute [tex]\( x \)[/tex] from the first binomial to both terms in the second binomial:
[tex]\[ x \cdot (x - 7) = x^2 - 7x \][/tex]

2. Distribute [tex]\( 3 \)[/tex] from the first binomial to both terms in the second binomial:
[tex]\[ 3 \cdot (x - 7) = 3x - 21 \][/tex]

3. Combine all the terms together:
[tex]\[ x^2 - 7x + 3x - 21 \][/tex]

4. Combine like terms (the [tex]\( -7x \)[/tex] and the [tex]\( 3x \)[/tex]):
[tex]\[ x^2 - 4x - 21 \][/tex]

So, the product of the binomials [tex]\( (x + 3)(x - 7) \)[/tex] is:
[tex]\[ x^2 - 4x - 21 \][/tex]