Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
To find the quotient and remainder when dividing [tex]\( x^2 - 4x + 8 \)[/tex] by [tex]\( x - 3 \)[/tex], we will use polynomial long division.
1. Set up the division:
[tex]\[ \frac{x^2 - 4x + 8}{x - 3} \][/tex]
2. Divide the first term of the numerator by the first term of the denominator:
[tex]\[ \frac{x^2}{x} = x \][/tex]
3. Multiply the whole divisor by this result (x) and subtract from the original numerator:
[tex]\[ (x^2 - 4x + 8) - (x \cdot (x - 3)) = (x^2 - 4x + 8) - (x^2 - 3x) = (-4x + 8) - (-3x) = -4x + 3x + 8 = -x + 8 \][/tex]
4. Repeat the process with the new polynomial (-x + 8):
[tex]\[ \frac{-x}{x} = -1 \][/tex]
5. Multiply the whole divisor by this result (-1) and subtract from the current polynomial:
[tex]\[ (-x + 8) - (-1 \cdot (x - 3)) = (-x + 8) - (-x + 3) = 8 - 3 = 5 \][/tex]
After these steps, the quotient is:
[tex]\[ \boxed{x - 1} \][/tex]
and the remainder is:
[tex]\[ \boxed{5} \][/tex]
1. Set up the division:
[tex]\[ \frac{x^2 - 4x + 8}{x - 3} \][/tex]
2. Divide the first term of the numerator by the first term of the denominator:
[tex]\[ \frac{x^2}{x} = x \][/tex]
3. Multiply the whole divisor by this result (x) and subtract from the original numerator:
[tex]\[ (x^2 - 4x + 8) - (x \cdot (x - 3)) = (x^2 - 4x + 8) - (x^2 - 3x) = (-4x + 8) - (-3x) = -4x + 3x + 8 = -x + 8 \][/tex]
4. Repeat the process with the new polynomial (-x + 8):
[tex]\[ \frac{-x}{x} = -1 \][/tex]
5. Multiply the whole divisor by this result (-1) and subtract from the current polynomial:
[tex]\[ (-x + 8) - (-1 \cdot (x - 3)) = (-x + 8) - (-x + 3) = 8 - 3 = 5 \][/tex]
After these steps, the quotient is:
[tex]\[ \boxed{x - 1} \][/tex]
and the remainder is:
[tex]\[ \boxed{5} \][/tex]
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.