Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

A boat can travel at an average speed of 10 miles per hour in still water. Traveling with the current, it can travel 6 miles in the same amount of time it takes to travel 4 miles upstream.

Use the relationship [tex]\( t = \frac{d}{r} \)[/tex] to construct a rational equation that can be solved for [tex]\( x \)[/tex] to find the speed of the current.

[tex]\[
\frac{6}{10 + x} = \frac{4}{10 - x}
\][/tex]

Solve for [tex]\( x \)[/tex].


Sagot :

To solve for the speed of the current, let's denote the speed of the boat in still water as [tex]\(10\)[/tex] miles per hour and let [tex]\(x\)[/tex] be the speed of the current in miles per hour.

When the boat travels with the current, its effective speed is [tex]\((10 + x)\)[/tex] miles per hour. The boat covers a distance of [tex]\(6\)[/tex] miles with the current. The time taken to travel these 6 miles is:
[tex]\[ \text{time with current} = \frac{6}{10 + x} \][/tex]

When the boat travels upstream against the current, its effective speed is [tex]\((10 - x)\)[/tex] miles per hour. The boat covers a distance of [tex]\(4\)[/tex] miles upstream. The time taken to travel these 4 miles is:
[tex]\[ \text{time upstream} = \frac{4}{10 - x} \][/tex]

Since the times taken to travel both distances are the same, we can set up the following rational equation:
[tex]\[ \frac{6}{10 + x} = \frac{4}{10 - x} \][/tex]