Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Alright Eli, let's work through this step by step and complete the table you have.
First, let's define what we have and need to find using the variables given:
1. 10% Acetic Acid Solution
- Volume: [tex]\(0.5\)[/tex] gallons
- Concentration: [tex]\(10\%\)[/tex] (or 0.10)
2. 35% Acetic Acid Solution
- Volume: [tex]\(v\)[/tex] gallons
- Concentration: [tex]\(35\%\)[/tex] (or 0.35)
3. Mixture
- Desired Concentration: [tex]\(15\%\)[/tex] (or 0.15)
- Total Volume: [tex]\(v + 0.5\)[/tex] gallons
Now, let's calculate the amounts as requested and complete the table. Here's the additional information needed for calculations:
- The amount of acetic acid in the [tex]\(10\%\)[/tex] solution is:
[tex]\[ 0.5 \text{ gallons} \times 0.10 = 0.05 \text{ gallons of acetic acid} \][/tex]
- The amount of acetic acid in the [tex]\(35\%\)[/tex] solution is:
[tex]\[ 0.35 v \text{ gallons of acetic acid} \][/tex]
- The total volume of the mixture:
[tex]\[ v + 0.5 \text{ gallons} \][/tex]
- The amount of acetic acid in the mixture:
[tex]\[ 0.15 (v + 0.5) \text{ gallons of acetic acid} \][/tex]
Given that we want the total amount of acetic acid in the mixture to be the sum of the amount from the [tex]\(10\%\)[/tex] and [tex]\(35\%\)[/tex] solutions, we can set up the equation:
[tex]\[ 0.05 + 0.35 v = 0.15 (v + 0.5) \][/tex]
From the values calculated:
[tex]\[ v = 0.125 \text{ gallons} \][/tex]
Now, let's fill out the required table with these values:
\begin{tabular}{|c|c|c|c|}
\hline \begin{tabular}{c}
Amount of \\
Solution
\end{tabular} & \begin{tabular}{c}
Acid \\
Concentration
\end{tabular} & \begin{tabular}{c}
Amount of \\
Acid
\end{tabular} \\
\hline
[tex]$10\%$[/tex] Acid & [tex]$0.5$[/tex] gal & [tex]$0.10$[/tex] & [tex]$(0.10)(0.5) = 0.05$[/tex] \\
\hline
[tex]$35\%$[/tex] Acid & [tex]$v = 0.125$[/tex] gal & [tex]$0.35$[/tex] & [tex]$0.35 (0.125) = 0.04375$[/tex] \\
\hline
Mixture & [tex]$v + 0.5 = 0.625$[/tex] gal & [tex]$0.15$[/tex] & [tex]$0.15 (0.625) = 0.09375$[/tex] \\
\hline
\end{tabular}
So, the filled table is:
> \begin{tabular}{|c|c|c|c|}
> \hline & \begin{tabular}{c}
> Amount of \\
> Solution
> \end{tabular} & \begin{tabular}{c}
> Acid \\
> Concentration
> \end{tabular} & \begin{tabular}{c}
> Amount of \\
> Acid
> \end{tabular} \\
> \hline [tex]$10\%$[/tex] Acid & [tex]$0.5$[/tex] gal & [tex]$0.10$[/tex] & [tex]$0.05$[/tex] \\
> \hline [tex]$35\%$[/tex] Acid & [tex]$0.125$[/tex] gal & [tex]$0.35$[/tex] & [tex]$0.04375$[/tex] \\
> \hline Mixture & [tex]$0.625$[/tex] gal & [tex]$0.15$[/tex] & [tex]$0.09375$[/tex] \\
> \hline
> \end{tabular}
This table now accurately represents the given problem and the quantities involved.
First, let's define what we have and need to find using the variables given:
1. 10% Acetic Acid Solution
- Volume: [tex]\(0.5\)[/tex] gallons
- Concentration: [tex]\(10\%\)[/tex] (or 0.10)
2. 35% Acetic Acid Solution
- Volume: [tex]\(v\)[/tex] gallons
- Concentration: [tex]\(35\%\)[/tex] (or 0.35)
3. Mixture
- Desired Concentration: [tex]\(15\%\)[/tex] (or 0.15)
- Total Volume: [tex]\(v + 0.5\)[/tex] gallons
Now, let's calculate the amounts as requested and complete the table. Here's the additional information needed for calculations:
- The amount of acetic acid in the [tex]\(10\%\)[/tex] solution is:
[tex]\[ 0.5 \text{ gallons} \times 0.10 = 0.05 \text{ gallons of acetic acid} \][/tex]
- The amount of acetic acid in the [tex]\(35\%\)[/tex] solution is:
[tex]\[ 0.35 v \text{ gallons of acetic acid} \][/tex]
- The total volume of the mixture:
[tex]\[ v + 0.5 \text{ gallons} \][/tex]
- The amount of acetic acid in the mixture:
[tex]\[ 0.15 (v + 0.5) \text{ gallons of acetic acid} \][/tex]
Given that we want the total amount of acetic acid in the mixture to be the sum of the amount from the [tex]\(10\%\)[/tex] and [tex]\(35\%\)[/tex] solutions, we can set up the equation:
[tex]\[ 0.05 + 0.35 v = 0.15 (v + 0.5) \][/tex]
From the values calculated:
[tex]\[ v = 0.125 \text{ gallons} \][/tex]
Now, let's fill out the required table with these values:
\begin{tabular}{|c|c|c|c|}
\hline \begin{tabular}{c}
Amount of \\
Solution
\end{tabular} & \begin{tabular}{c}
Acid \\
Concentration
\end{tabular} & \begin{tabular}{c}
Amount of \\
Acid
\end{tabular} \\
\hline
[tex]$10\%$[/tex] Acid & [tex]$0.5$[/tex] gal & [tex]$0.10$[/tex] & [tex]$(0.10)(0.5) = 0.05$[/tex] \\
\hline
[tex]$35\%$[/tex] Acid & [tex]$v = 0.125$[/tex] gal & [tex]$0.35$[/tex] & [tex]$0.35 (0.125) = 0.04375$[/tex] \\
\hline
Mixture & [tex]$v + 0.5 = 0.625$[/tex] gal & [tex]$0.15$[/tex] & [tex]$0.15 (0.625) = 0.09375$[/tex] \\
\hline
\end{tabular}
So, the filled table is:
> \begin{tabular}{|c|c|c|c|}
> \hline & \begin{tabular}{c}
> Amount of \\
> Solution
> \end{tabular} & \begin{tabular}{c}
> Acid \\
> Concentration
> \end{tabular} & \begin{tabular}{c}
> Amount of \\
> Acid
> \end{tabular} \\
> \hline [tex]$10\%$[/tex] Acid & [tex]$0.5$[/tex] gal & [tex]$0.10$[/tex] & [tex]$0.05$[/tex] \\
> \hline [tex]$35\%$[/tex] Acid & [tex]$0.125$[/tex] gal & [tex]$0.35$[/tex] & [tex]$0.04375$[/tex] \\
> \hline Mixture & [tex]$0.625$[/tex] gal & [tex]$0.15$[/tex] & [tex]$0.09375$[/tex] \\
> \hline
> \end{tabular}
This table now accurately represents the given problem and the quantities involved.
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.