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A 18 kg capybara runs at a speed of 6 m/s at a height of 5 m. Find the kinetic and potential
energy of the capybara


Sagot :

Answer:

324 J in Kinetic energy

882 J in Potential energy

Explanation:

Given:

  • Mass - 18 kg
  • Velocity - 6ms^-1
  • Height - 5m

To find the Kinetic energy and Potential energy of the capybara, we need to use their various formula

Kinetic Energy

[tex] \boxed{ \rightarrow KE = \frac{1}{2}mv^2}[/tex]

Where:

  • KE represents kinetic energy
  • m stands for abbreviation regarding "mass"
  • v representing velocity

[tex] \sf KE = \frac{1}{2} \times 18kg \times{ (6ms^{- 1})}^{2} [/tex]

[tex] \sf KE = \frac{1}{2} \times 18kg \times 36ms^{- 2}[/tex]

[tex] \sf KE = \frac{1}{2} \times 648kg \times ms^{- 2}[/tex]

[tex] \sf KE = 324kg \times {ms}^{ - 2} = 324 \: \text{joules}[/tex]

Therefore, the Kinetic energy of the capybara simplifies to 324 Joules.

Potential Energy

[tex] \boxed{ \rightarrow PE = mgh}[/tex]

Where:

  • PE represents potential energy
  • m represents mass
  • h represents the height

[tex] \sf PE = 18kg \times 9.8 {ms}^{ - 2} \times 5m[/tex]

[tex] \sf PE = 882kg \times {ms}^{ - 2} \times m[/tex]

[tex] \sf PE = 882 \: \text{joules}[/tex]

Therefore, the Potential energy of the capybara simplifies to 882 Joules.