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To determine which of the given compounds has the largest percent by mass of oxygen, let's break down the problem step-by-step:
1. Determine the molar mass of each compound:
- For [tex]\( CH_2O \)[/tex]:
[tex]\[ \text{Molar mass} = 12 (\text{C}) + 2 \times 1 (\text{H}) + 16 (\text{O}) = 12 + 2 + 16 = 30 \text{g/mol} \][/tex]
- For [tex]\( CO_2 \)[/tex]:
[tex]\[ \text{Molar mass} = 12 (\text{C}) + 2 \times 16 (\text{O}) = 12 + 32 = 44 \text{g/mol} \][/tex]
- For [tex]\( C_6H_{12}O_6 \)[/tex]:
[tex]\[ \text{Molar mass} = 6 \times 12 (\text{C}) + 12 \times 1 (\text{H}) + 6 \times 16 (\text{O}) = 72 + 12 + 96 = 180 \text{g/mol} \][/tex]
- For [tex]\( CO \)[/tex]:
[tex]\[ \text{Molar mass} = 12 (\text{C}) + 16 (\text{O}) = 12 + 16 = 28 \text{g/mol} \][/tex]
2. Calculate the mass of oxygen in each compound:
- For [tex]\( CH_2O \)[/tex]:
[tex]\[ \text{Mass of oxygen} = 16 \text{g} \][/tex]
- For [tex]\( CO_2 \)[/tex]:
[tex]\[ \text{Mass of oxygen} = 2 \times 16 = 32 \text{g} \][/tex]
- For [tex]\( C_6H_{12}O_6 \)[/tex]:
[tex]\[ \text{Mass of oxygen} = 6 \times 16 = 96 \text{g} \][/tex]
- For [tex]\( CO \)[/tex]:
[tex]\[ \text{Mass of oxygen} = 16 \text{g} \][/tex]
3. Calculate the percent by mass of oxygen in each compound:
- For [tex]\( CH_2O \)[/tex]:
[tex]\[ \text{Percent by mass of oxygen} = \left( \frac{16}{30} \right) \times 100 = 53.33\% \][/tex]
- For [tex]\( CO_2 \)[/tex]:
[tex]\[ \text{Percent by mass of oxygen} = \left( \frac{32}{44} \right) \times 100 = 72.73\% \][/tex]
- For [tex]\( C_6H_{12}O_6 \)[/tex]:
[tex]\[ \text{Percent by mass of oxygen} = \left( \frac{96}{180} \right) \times 100 = 53.33\% \][/tex]
- For [tex]\( CO \)[/tex]:
[tex]\[ \text{Percent by mass of oxygen} = \left( \frac{16}{28} \right) \times 100 = 57.14\% \][/tex]
4. Determine the compound with the largest percent by mass of oxygen:
- [tex]\( CH_2O \)[/tex]: [tex]\( 53.33\% \)[/tex]
- [tex]\( CO_2 \)[/tex]: [tex]\( 72.73\% \)[/tex]
- [tex]\( C_6H_{12}O_6 \)[/tex]: [tex]\( 53.33\% \)[/tex]
- [tex]\( CO \)[/tex]: [tex]\( 57.14\% \)[/tex]
Among these, the compound [tex]\( CO_2 \)[/tex] has the largest percent by mass of oxygen.
Therefore, the compound with the largest percent by mass of oxygen is [tex]\[ \boxed{CO_2} \][/tex]
1. Determine the molar mass of each compound:
- For [tex]\( CH_2O \)[/tex]:
[tex]\[ \text{Molar mass} = 12 (\text{C}) + 2 \times 1 (\text{H}) + 16 (\text{O}) = 12 + 2 + 16 = 30 \text{g/mol} \][/tex]
- For [tex]\( CO_2 \)[/tex]:
[tex]\[ \text{Molar mass} = 12 (\text{C}) + 2 \times 16 (\text{O}) = 12 + 32 = 44 \text{g/mol} \][/tex]
- For [tex]\( C_6H_{12}O_6 \)[/tex]:
[tex]\[ \text{Molar mass} = 6 \times 12 (\text{C}) + 12 \times 1 (\text{H}) + 6 \times 16 (\text{O}) = 72 + 12 + 96 = 180 \text{g/mol} \][/tex]
- For [tex]\( CO \)[/tex]:
[tex]\[ \text{Molar mass} = 12 (\text{C}) + 16 (\text{O}) = 12 + 16 = 28 \text{g/mol} \][/tex]
2. Calculate the mass of oxygen in each compound:
- For [tex]\( CH_2O \)[/tex]:
[tex]\[ \text{Mass of oxygen} = 16 \text{g} \][/tex]
- For [tex]\( CO_2 \)[/tex]:
[tex]\[ \text{Mass of oxygen} = 2 \times 16 = 32 \text{g} \][/tex]
- For [tex]\( C_6H_{12}O_6 \)[/tex]:
[tex]\[ \text{Mass of oxygen} = 6 \times 16 = 96 \text{g} \][/tex]
- For [tex]\( CO \)[/tex]:
[tex]\[ \text{Mass of oxygen} = 16 \text{g} \][/tex]
3. Calculate the percent by mass of oxygen in each compound:
- For [tex]\( CH_2O \)[/tex]:
[tex]\[ \text{Percent by mass of oxygen} = \left( \frac{16}{30} \right) \times 100 = 53.33\% \][/tex]
- For [tex]\( CO_2 \)[/tex]:
[tex]\[ \text{Percent by mass of oxygen} = \left( \frac{32}{44} \right) \times 100 = 72.73\% \][/tex]
- For [tex]\( C_6H_{12}O_6 \)[/tex]:
[tex]\[ \text{Percent by mass of oxygen} = \left( \frac{96}{180} \right) \times 100 = 53.33\% \][/tex]
- For [tex]\( CO \)[/tex]:
[tex]\[ \text{Percent by mass of oxygen} = \left( \frac{16}{28} \right) \times 100 = 57.14\% \][/tex]
4. Determine the compound with the largest percent by mass of oxygen:
- [tex]\( CH_2O \)[/tex]: [tex]\( 53.33\% \)[/tex]
- [tex]\( CO_2 \)[/tex]: [tex]\( 72.73\% \)[/tex]
- [tex]\( C_6H_{12}O_6 \)[/tex]: [tex]\( 53.33\% \)[/tex]
- [tex]\( CO \)[/tex]: [tex]\( 57.14\% \)[/tex]
Among these, the compound [tex]\( CO_2 \)[/tex] has the largest percent by mass of oxygen.
Therefore, the compound with the largest percent by mass of oxygen is [tex]\[ \boxed{CO_2} \][/tex]
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