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A team of dogs pulls a sled across the snow. The weight of the loaded sled is 2200 N. The coefficient of friction is 0.15. How hard must the dogs pull so that their effort just equals the frictional force?

A. 15,000 N
B. 34 N
C. 330 N
D. 220 N


Sagot :

To determine how hard the dogs must pull to overcome the frictional force, we need to calculate the frictional force acting on the sled. Here's a step-by-step solution:

1. Identify the given values:
- Weight of the sled, [tex]\( W \)[/tex] = [tex]\( 2200 \)[/tex] N
- Coefficient of friction, [tex]\( \mu \)[/tex] = [tex]\( 0.15 \)[/tex]

2. Understand the relationship between frictional force and the given values:
The frictional force [tex]\( F_{\text{friction}} \)[/tex] can be calculated using the formula:
[tex]\[ F_{\text{friction}} = \mu \times N \][/tex]
where [tex]\( N \)[/tex] is the normal force. On a flat surface, the normal force [tex]\( N \)[/tex] equals the weight of the sled, which is [tex]\( 2200 \)[/tex] N.

3. Plug in the values into the formula:
[tex]\[ F_{\text{friction}} = 0.15 \times 2200 \][/tex]

4. Calculate the result:
[tex]\[ F_{\text{friction}} = 0.15 \times 2200 = 330 \text{ N} \][/tex]

Therefore, the dogs must pull with a force of [tex]\( 330 \)[/tex] N to overcome the frictional force and move the sled.

The correct answer is:
[tex]\[ \boxed{330 \text{ N}} \][/tex]