Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Determine the amplitude, period, and phase shift of the following trigonometric equation:

[tex]\[ y = \frac{-5}{3} \sin \left(\frac{\pi}{3} x\right) \][/tex]

Answer:

Amplitude: [tex]\(\square\)[/tex]

Phase Shift:
- no phase shift
- shifted to the right
- shifted to the left


Sagot :

To determine the amplitude, period, and phase shift of the trigonometric equation [tex]\( y=\frac{-5}{3} \sin \left(\frac{\pi}{3} x\right) \)[/tex], we'll follow these steps.

### Step-by-Step Solution:

#### 1. Amplitude:
The amplitude of a sinusoidal function of the form [tex]\( y = A \sin(Bx + C) \)[/tex] or [tex]\( y = A \cos(Bx + C) \)[/tex] is given by the absolute value of [tex]\( A \)[/tex].

In the given equation [tex]\( y=\frac{-5}{3} \sin \left(\frac{\pi}{3} x\right) \)[/tex]:
- [tex]\( A = \frac{-5}{3} \)[/tex]
- The amplitude is [tex]\( |A| = \left|\frac{-5}{3}\right| = \frac{5}{3} \)[/tex].

So, the amplitude is:
[tex]\[ \frac{5}{3} \][/tex]

#### 2. Period:
The period of a sinusoidal function [tex]\( y = A \sin(Bx + C) \)[/tex] or [tex]\( y = A \cos(Bx + C) \)[/tex] is calculated using the coefficient [tex]\( B \)[/tex] inside the function. The formula for the period is:
[tex]\[ \text{Period} = \frac{2\pi}{B} \][/tex]

In the given equation [tex]\( y=\frac{-5}{3} \sin \left(\frac{\pi}{3} x\right) \)[/tex]:
- [tex]\( B = \frac{\pi}{3} \)[/tex]
- The period is:
[tex]\[ \text{Period} = \frac{2\pi}{\frac{\pi}{3}} = 2\pi \times \frac{3}{\pi} = 6 \][/tex]

So, the period is:
[tex]\[ 6 \][/tex]

#### 3. Phase Shift:
The phase shift of a sinusoidal function [tex]\( y = A \sin(Bx + C) \)[/tex] or [tex]\( y = A \cos(Bx + C) \)[/tex] is determined from the horizontal shift within the function. The general formula to find the phase shift is:
[tex]\[ \text{Phase Shift} = -\frac{C}{B} \][/tex]

In the given equation [tex]\( y=\frac{-5}{3} \sin \left(\frac{\pi}{3} x\right) \)[/tex]:
- There is no [tex]\( C \)[/tex] term present (i.e., [tex]\( C = 0 \)[/tex])

Since [tex]\( C = 0 \)[/tex]:
[tex]\[ \text{Phase Shift} = -\frac{0}{\frac{\pi}{3}} = 0 \][/tex]

So, there is no phase shift.

### Summary:
- Amplitude: [tex]\( \frac{5}{3} \)[/tex]
- Period: [tex]\( 6 \)[/tex]
- Phase Shift: No phase shift.

Finally, we can conclude:

- Amplitude: [tex]\( 1.6666666666666667 \)[/tex]
- Period: [tex]\( 6.0 \)[/tex]
- Phase Shift: no phase shift