Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Which table represents an exponential function of the form [tex]\( y = b^x \)[/tex] when [tex]\( 0 \ \textless \ b \ \textless \ 1 \)[/tex]?

[tex]\[
\begin{tabular}{|c|c|}
\hline
x & y \\
\hline
-3 & \frac{1}{27} \\
\hline
-2 & \frac{1}{9} \\
\hline
-1 & \frac{1}{3} \\
\hline
0 & 1 \\
\hline
1 & 3 \\
\hline
2 & 9 \\
\hline
3 & 27 \\
\hline
\end{tabular}
\][/tex]

[tex]\[
\begin{tabular}{|c|c|}
\hline
x & y \\
\hline
-3 & 27 \\
\hline
-2 & 9 \\
\hline
-1 & 3 \\
\hline
0 & 1 \\
\hline
1 & \frac{1}{3} \\
\hline
2 & \frac{1}{9} \\
\hline
3 & \frac{1}{27} \\
\hline
\end{tabular}
\][/tex]

Sagot :

GinnyAnswer
To determine which table represents an exponential function of the form [tex]\( y = b^x \)[/tex] with [tex]\( 0 < b < 1 \)[/tex], let's analyze each table carefully.

### First Table Analysis:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline -3 & \frac{1}{27} \\ \hline -2 & \frac{1}{9} \\ \hline -2 & \frac{1}{3} \\ \hline 0 & 1 \\ \hline 1 & 3 \\ \hline 2 & 9 \\ \hline 3 & 27 \\ \hline \end{array} \][/tex]

- For [tex]\( x = -3 \)[/tex] to [tex]\( x = -2 \)[/tex]: [tex]\( \frac{1/9}{1/27} = 3 \)[/tex]
- For [tex]\( x = -2 \)[/tex] to [tex]\( x = 0 \)[/tex]: [tex]\( \frac{1}{1/9} = 9 \)[/tex]
- For [tex]\( x = 0 \)[/tex] to [tex]\( x = 2 \)[/tex]: [tex]\( \frac{9}{1} = 9 \)[/tex]
- For [tex]\( x = 2 \)[/tex] to [tex]\( x = 3 \)[/tex]: [tex]\( \frac{27}{9} = 3 \)[/tex]

We can see that the values don't maintain a consistent ratio, suggesting it is not an exponential function of the desired form.

### Second Table Analysis:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline -3 & 27 \\ \hline -2 & 9 \\ \hline -1 & 3 \\ \hline 0 & 1 \\ \hline 1 & \frac{1}{3} \\ \hline 2 & \frac{1}{9} \\ \hline 3 & \frac{1}{27} \\ \hline \end{array} \][/tex]

- For [tex]\( x = -3 \)[/tex] to [tex]\( x = -2 \)[/tex]: [tex]\( \frac{9}{27} = \frac{1}{3} \)[/tex]
- For [tex]\( x = -2 \)[/tex] to [tex]\( x = -1 \)[/tex]: [tex]\( \frac{3}{9} = \frac{1}{3} \)[/tex]
- For [tex]\( x = -1 \)[/tex] to [tex]\( x = 0 \)[/tex]: [tex]\( \frac{1}{3} = \frac{1}{3} \)[/tex]
- For [tex]\( x = 0 \)[/tex] to [tex]\( x = 1 \)[/tex]: [tex]\( \frac{1/3}{1} = \frac{1}{3} \)[/tex]
- For [tex]\( x = 1 \)[/tex] to [tex]\( x = 2 \)[/tex]: [tex]\( \frac{1/9}{1/3} = \frac{1}{3} \)[/tex]
- For [tex]\( x = 2 \)[/tex] to [tex]\( x = 3 \)[/tex]: [tex]\( \frac{1/27}{1/9} = \frac{1}{3} \)[/tex]

Each ratio [tex]\( \frac{y_{n+1}}{y_{n}} \)[/tex] is [tex]\( \frac{1}{3} \)[/tex], which is consistent and within the range [tex]\( 0 < b < 1 \)[/tex].

Therefore, the second table represents an exponential function of the form [tex]\( y = b^x \)[/tex] with [tex]\( 0 < b < 1 \)[/tex].

The table number is [tex]\( \boxed{2} \)[/tex].
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.