Let's solve the problem step by step to determine which salt is produced when sulfuric acid (H[tex]\(_2\)[/tex]SO[tex]\(_4\)[/tex]) reacts with sodium hydroxide (NaOH).
1. Identify the reactants:
The reactants in this chemical reaction are sulfuric acid (H[tex]\(_2\)[/tex]SO[tex]\(_4\)[/tex]) and sodium hydroxide (NaOH).
2. Write the balanced chemical equation:
To find the products of this reaction, we need to write the balanced chemical equation. When sulfuric acid (a strong acid) reacts with sodium hydroxide (a strong base), a neutralization reaction occurs, producing a salt and water.
The general form of a neutralization reaction is:
[tex]\[ \text{Acid} + \text{Base} \rightarrow \text{Salt} + \text{Water} \][/tex]
For sulfuric acid reacting with sodium hydroxide, the balanced equation is:
[tex]\[ H_2SO_4 + 2NaOH \rightarrow Na_2SO_4 + 2H_2O \][/tex]
3. Determine the salt produced:
From the balanced chemical equation, we see that the salt formed in this reaction is sodium sulfate (Na[tex]\(_2\)[/tex]SO[tex]\(_4\)[/tex]).
4. Evaluate the given options:
- [tex]\(K_2SO_3\)[/tex]
- [tex]\(Na_2SO_4\)[/tex]
- [tex]\(Na_2SO_3\)[/tex]
- [tex]\(K_2SO_4\)[/tex]
5. Select the correct option:
According to the balanced chemical equation, the salt produced is sodium sulfate (Na[tex]\(_2\)[/tex]SO[tex]\(_4\)[/tex]). Therefore, the correct answer is [tex]\(Na_2SO_4\)[/tex].
Hence, when [tex]\(H_2SO_4\)[/tex] reacts with [tex]\(NaOH\)[/tex], the salt produced is:
[tex]\[\boxed{Na_2SO_4}\][/tex]
