Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

If the cos of angle [tex]\( x \)[/tex] is [tex]\(\frac{8}{17}\)[/tex] and the triangle is dilated to twice its original size, what is the value of cos [tex]\( x \)[/tex] for the dilated triangle?

A. [tex]\( \frac{8}{17} \)[/tex]

Sagot :

GinnyAnswer
The problem states that the cosine of angle [tex]\( x \)[/tex] in the original triangle is given by [tex]\( \frac{8}{17} \)[/tex].

When a triangle is dilated, the angles within the triangle remain unchanged. Dilation involves scaling all sides of the triangle by the same factor, which does not affect the internal angles of the triangle. Therefore, the trigonometric ratios, which are dependent only on the angles, also remain unchanged.

Hence, the value of [tex]\( \cos(x) \)[/tex] for the dilated triangle is the same as the value of [tex]\( \cos(x) \)[/tex] for the original triangle.

Thus, the value of [tex]\( \cos(x) \)[/tex] for the dilated triangle is:
[tex]\[ \frac{8}{17} \][/tex]
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.