Answered

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A big jar of nickels and dimes contained $30. if 500 coins were in the jar how many of each were on there?

Sagot :

Answer:

nickel  = 200 coins

dimes = 300 coins

Step-by-step explanation:

let x be the nickels and

let y be the dimes

as per given:

x + y = 500                           (1)

$.000134x + $.10y = $30    (2)

from equation (1)

x = 500 - y                           (3)

substituting the value of x from equation (3) into equation (2)

.000134(500 - y) + .10y = 30

.067 - .000134y + .10y = 30

.099866y = 30 - .067

y = 29.933 / .099866

  = 299.73 = 300 dimes     (4)

substituting the value of y from equation (4) into equation (3)

x = 500 - 300 = 200 nickels

thus,

nickel  = 200 coins

dimes = 300 coins

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