At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Certainly! Let's analyze the function [tex]\( y = x^4 - 31x^2 - 180 \)[/tex] step by step to find the intercepts and test for symmetry.
### Intercepts
#### Y-Intercept
The y-intercept happens where the function crosses the y-axis. To find the y-intercept, we set [tex]\( x = 0 \)[/tex] in the function.
[tex]\[ y = (0)^4 - 31(0)^2 - 180 \][/tex]
[tex]\[ y = -180 \][/tex]
So, the y-intercept is [tex]\((0, -180)\)[/tex].
#### X-Intercepts
The x-intercepts occur where the function crosses the x-axis. To find the x-intercepts, we set [tex]\( y = 0 \)[/tex] and solve for [tex]\( x \)[/tex].
[tex]\[ 0 = x^4 - 31x^2 - 180 \][/tex]
This equation needs to be solved for [tex]\( x \)[/tex]. The solutions to this equation are:
[tex]\[ x = -6, \quad x = 6, \quad x = -\sqrt{5}i, \quad x = \sqrt{5}i \][/tex]
However, [tex]\( -\sqrt{5}i \)[/tex] and [tex]\( \sqrt{5}i \)[/tex] are complex numbers and thus, do not represent real intercepts on the Cartesian plane. The real x-intercepts are:
[tex]\[ x = -6 \quad \text{and} \quad x = 6 \][/tex]
So, the real x-intercepts are [tex]\((-6, 0)\)[/tex] and [tex]\((6, 0)\)[/tex].
### Symmetry
Let's test for symmetry of the function around the y-axis and the origin:
#### Symmetry around the Y-Axis
A function is symmetric around the y-axis if [tex]\( f(x) = f(-x) \)[/tex].
[tex]\[ y = x^4 - 31x^2 - 180 \][/tex]
[tex]\[ y(-x) = (-x)^4 - 31(-x)^2 - 180 \][/tex]
[tex]\[ y(-x) = x^4 - 31x^2 - 180 \][/tex]
Since [tex]\( y(x) = y(-x) \)[/tex], the function is symmetric around the y-axis.
#### Symmetry around the X-Axis
Symmetry around the x-axis would require [tex]\( f(x) = -f(x) \)[/tex], but this is not generally the case for functions defined as [tex]\( y = f(x) \)[/tex].
#### Symmetry around the Origin
A function is symmetric around the origin if [tex]\( f(x) = -f(-x) \)[/tex].
[tex]\[ y = x^4 - 31x^2 - 180 \][/tex]
[tex]\[ -y(-x) = -(x^4 - 31x^2 - 180) \][/tex]
[tex]\[ -y(-x) = -x^4 + 31x^2 + 180 \][/tex]
Since [tex]\( y(x) \neq -y(-x) \)[/tex], the function is not symmetric around the origin.
### Conclusion
- Y-Intercept: [tex]\((0, -180)\)[/tex]
- X-Intercepts: [tex]\((-6, 0)\)[/tex] and [tex]\((6, 0)\)[/tex]
- Symmetry:
- The function is symmetric around the y-axis.
- The function is not symmetric around the origin.
### Intercepts
#### Y-Intercept
The y-intercept happens where the function crosses the y-axis. To find the y-intercept, we set [tex]\( x = 0 \)[/tex] in the function.
[tex]\[ y = (0)^4 - 31(0)^2 - 180 \][/tex]
[tex]\[ y = -180 \][/tex]
So, the y-intercept is [tex]\((0, -180)\)[/tex].
#### X-Intercepts
The x-intercepts occur where the function crosses the x-axis. To find the x-intercepts, we set [tex]\( y = 0 \)[/tex] and solve for [tex]\( x \)[/tex].
[tex]\[ 0 = x^4 - 31x^2 - 180 \][/tex]
This equation needs to be solved for [tex]\( x \)[/tex]. The solutions to this equation are:
[tex]\[ x = -6, \quad x = 6, \quad x = -\sqrt{5}i, \quad x = \sqrt{5}i \][/tex]
However, [tex]\( -\sqrt{5}i \)[/tex] and [tex]\( \sqrt{5}i \)[/tex] are complex numbers and thus, do not represent real intercepts on the Cartesian plane. The real x-intercepts are:
[tex]\[ x = -6 \quad \text{and} \quad x = 6 \][/tex]
So, the real x-intercepts are [tex]\((-6, 0)\)[/tex] and [tex]\((6, 0)\)[/tex].
### Symmetry
Let's test for symmetry of the function around the y-axis and the origin:
#### Symmetry around the Y-Axis
A function is symmetric around the y-axis if [tex]\( f(x) = f(-x) \)[/tex].
[tex]\[ y = x^4 - 31x^2 - 180 \][/tex]
[tex]\[ y(-x) = (-x)^4 - 31(-x)^2 - 180 \][/tex]
[tex]\[ y(-x) = x^4 - 31x^2 - 180 \][/tex]
Since [tex]\( y(x) = y(-x) \)[/tex], the function is symmetric around the y-axis.
#### Symmetry around the X-Axis
Symmetry around the x-axis would require [tex]\( f(x) = -f(x) \)[/tex], but this is not generally the case for functions defined as [tex]\( y = f(x) \)[/tex].
#### Symmetry around the Origin
A function is symmetric around the origin if [tex]\( f(x) = -f(-x) \)[/tex].
[tex]\[ y = x^4 - 31x^2 - 180 \][/tex]
[tex]\[ -y(-x) = -(x^4 - 31x^2 - 180) \][/tex]
[tex]\[ -y(-x) = -x^4 + 31x^2 + 180 \][/tex]
Since [tex]\( y(x) \neq -y(-x) \)[/tex], the function is not symmetric around the origin.
### Conclusion
- Y-Intercept: [tex]\((0, -180)\)[/tex]
- X-Intercepts: [tex]\((-6, 0)\)[/tex] and [tex]\((6, 0)\)[/tex]
- Symmetry:
- The function is symmetric around the y-axis.
- The function is not symmetric around the origin.
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.