Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Certainly! Let's analyze the function [tex]\( y = x^4 - 31x^2 - 180 \)[/tex] step by step to find the intercepts and test for symmetry.
### Intercepts
#### Y-Intercept
The y-intercept happens where the function crosses the y-axis. To find the y-intercept, we set [tex]\( x = 0 \)[/tex] in the function.
[tex]\[ y = (0)^4 - 31(0)^2 - 180 \][/tex]
[tex]\[ y = -180 \][/tex]
So, the y-intercept is [tex]\((0, -180)\)[/tex].
#### X-Intercepts
The x-intercepts occur where the function crosses the x-axis. To find the x-intercepts, we set [tex]\( y = 0 \)[/tex] and solve for [tex]\( x \)[/tex].
[tex]\[ 0 = x^4 - 31x^2 - 180 \][/tex]
This equation needs to be solved for [tex]\( x \)[/tex]. The solutions to this equation are:
[tex]\[ x = -6, \quad x = 6, \quad x = -\sqrt{5}i, \quad x = \sqrt{5}i \][/tex]
However, [tex]\( -\sqrt{5}i \)[/tex] and [tex]\( \sqrt{5}i \)[/tex] are complex numbers and thus, do not represent real intercepts on the Cartesian plane. The real x-intercepts are:
[tex]\[ x = -6 \quad \text{and} \quad x = 6 \][/tex]
So, the real x-intercepts are [tex]\((-6, 0)\)[/tex] and [tex]\((6, 0)\)[/tex].
### Symmetry
Let's test for symmetry of the function around the y-axis and the origin:
#### Symmetry around the Y-Axis
A function is symmetric around the y-axis if [tex]\( f(x) = f(-x) \)[/tex].
[tex]\[ y = x^4 - 31x^2 - 180 \][/tex]
[tex]\[ y(-x) = (-x)^4 - 31(-x)^2 - 180 \][/tex]
[tex]\[ y(-x) = x^4 - 31x^2 - 180 \][/tex]
Since [tex]\( y(x) = y(-x) \)[/tex], the function is symmetric around the y-axis.
#### Symmetry around the X-Axis
Symmetry around the x-axis would require [tex]\( f(x) = -f(x) \)[/tex], but this is not generally the case for functions defined as [tex]\( y = f(x) \)[/tex].
#### Symmetry around the Origin
A function is symmetric around the origin if [tex]\( f(x) = -f(-x) \)[/tex].
[tex]\[ y = x^4 - 31x^2 - 180 \][/tex]
[tex]\[ -y(-x) = -(x^4 - 31x^2 - 180) \][/tex]
[tex]\[ -y(-x) = -x^4 + 31x^2 + 180 \][/tex]
Since [tex]\( y(x) \neq -y(-x) \)[/tex], the function is not symmetric around the origin.
### Conclusion
- Y-Intercept: [tex]\((0, -180)\)[/tex]
- X-Intercepts: [tex]\((-6, 0)\)[/tex] and [tex]\((6, 0)\)[/tex]
- Symmetry:
- The function is symmetric around the y-axis.
- The function is not symmetric around the origin.
### Intercepts
#### Y-Intercept
The y-intercept happens where the function crosses the y-axis. To find the y-intercept, we set [tex]\( x = 0 \)[/tex] in the function.
[tex]\[ y = (0)^4 - 31(0)^2 - 180 \][/tex]
[tex]\[ y = -180 \][/tex]
So, the y-intercept is [tex]\((0, -180)\)[/tex].
#### X-Intercepts
The x-intercepts occur where the function crosses the x-axis. To find the x-intercepts, we set [tex]\( y = 0 \)[/tex] and solve for [tex]\( x \)[/tex].
[tex]\[ 0 = x^4 - 31x^2 - 180 \][/tex]
This equation needs to be solved for [tex]\( x \)[/tex]. The solutions to this equation are:
[tex]\[ x = -6, \quad x = 6, \quad x = -\sqrt{5}i, \quad x = \sqrt{5}i \][/tex]
However, [tex]\( -\sqrt{5}i \)[/tex] and [tex]\( \sqrt{5}i \)[/tex] are complex numbers and thus, do not represent real intercepts on the Cartesian plane. The real x-intercepts are:
[tex]\[ x = -6 \quad \text{and} \quad x = 6 \][/tex]
So, the real x-intercepts are [tex]\((-6, 0)\)[/tex] and [tex]\((6, 0)\)[/tex].
### Symmetry
Let's test for symmetry of the function around the y-axis and the origin:
#### Symmetry around the Y-Axis
A function is symmetric around the y-axis if [tex]\( f(x) = f(-x) \)[/tex].
[tex]\[ y = x^4 - 31x^2 - 180 \][/tex]
[tex]\[ y(-x) = (-x)^4 - 31(-x)^2 - 180 \][/tex]
[tex]\[ y(-x) = x^4 - 31x^2 - 180 \][/tex]
Since [tex]\( y(x) = y(-x) \)[/tex], the function is symmetric around the y-axis.
#### Symmetry around the X-Axis
Symmetry around the x-axis would require [tex]\( f(x) = -f(x) \)[/tex], but this is not generally the case for functions defined as [tex]\( y = f(x) \)[/tex].
#### Symmetry around the Origin
A function is symmetric around the origin if [tex]\( f(x) = -f(-x) \)[/tex].
[tex]\[ y = x^4 - 31x^2 - 180 \][/tex]
[tex]\[ -y(-x) = -(x^4 - 31x^2 - 180) \][/tex]
[tex]\[ -y(-x) = -x^4 + 31x^2 + 180 \][/tex]
Since [tex]\( y(x) \neq -y(-x) \)[/tex], the function is not symmetric around the origin.
### Conclusion
- Y-Intercept: [tex]\((0, -180)\)[/tex]
- X-Intercepts: [tex]\((-6, 0)\)[/tex] and [tex]\((6, 0)\)[/tex]
- Symmetry:
- The function is symmetric around the y-axis.
- The function is not symmetric around the origin.
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.