Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Which are the roots of [tex]\( 81x^2 = 144 \)[/tex]?

A. [tex]\( x = \pm \frac{4}{3} \)[/tex]
B. [tex]\( x = -1 \)[/tex]
C. [tex]\( x = \frac{4}{3} \)[/tex]
D. [tex]\( x = \pm 1 \)[/tex]


Sagot :

To find the roots of the equation [tex]\(81x^2 = 144\)[/tex], let's follow a step-by-step solution:

1. Start with the given equation:
[tex]\[ 81x^2 = 144 \][/tex]

2. Divide both sides of the equation by 81 to isolate [tex]\(x^2\)[/tex]:
[tex]\[ x^2 = \frac{144}{81} \][/tex]

3. Simplify the fraction on the right-hand side:
[tex]\[ x^2 = \frac{16}{9} \][/tex]

4. Take the square root of both sides to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \pm \sqrt{\frac{16}{9}} \][/tex]

5. Simplify the square root:
[tex]\[ x = \pm \frac{4}{3} \][/tex]

Thus, the roots of the equation [tex]\(81x^2 = 144\)[/tex] are [tex]\(x = \frac{4}{3}\)[/tex] and [tex]\(x = -\frac{4}{3}\)[/tex].

So, the correct answer is:
[tex]\[ x = \pm \frac{4}{3} \][/tex]