At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To find the mean of the data summarized in the given frequency distribution, we will follow these steps:
1. Determine the midpoints for each interval:
- For the interval [tex]\(40-44\)[/tex], the midpoint is [tex]\((40 + 44) / 2 = 42\)[/tex].
- For the interval [tex]\(45-49\)[/tex], the midpoint is [tex]\((45 + 49) / 2 = 47\)[/tex].
- For the interval [tex]\(50-54\)[/tex], the midpoint is [tex]\((50 + 54) / 2 = 52\)[/tex].
- For the interval [tex]\(55-59\)[/tex], the midpoint is [tex]\((55 + 59) / 2 = 57\)[/tex].
- For the interval [tex]\(60-64\)[/tex], the midpoint is [tex]\((60 + 64) / 2 = 62\)[/tex].
2. List the midpoints and their corresponding frequencies:
[tex]\[ \begin{array}{cc} \text{Midpoint} & \text{Frequency} \\ \hline 42 & 3 \\ 47 & 6 \\ 52 & 12 \\ 57 & 7 \\ 62 & 3 \\ \end{array} \][/tex]
3. Calculate the weighted sum of the midpoints:
- Multiply each midpoint by its corresponding frequency and sum the results:
[tex]\[ (42 \times 3) + (47 \times 6) + (52 \times 12) + (57 \times 7) + (62 \times 3) \][/tex]
[tex]\[ = 126 + 282 + 624 + 399 + 186 \][/tex]
[tex]\[ = 1617 \][/tex]
4. Calculate the total number of data points:
- Sum the frequencies:
[tex]\[ 3 + 6 + 12 + 7 + 3 = 31 \][/tex]
5. Find the mean of the frequency distribution:
- Divide the weighted sum of the midpoints by the total number of data points:
[tex]\[ \text{Mean} = \frac{1617}{31} \approx 52.161 \][/tex]
- Rounded to the nearest tenth:
[tex]\[ \text{Mean} \approx 52.2 \][/tex]
So, the mean of the frequency distribution is approximately [tex]\(52.2\)[/tex] degrees.
When comparing this computed mean to the actual mean of [tex]\(56.4\)[/tex] degrees, we observe that the computed mean is lower. This indicates that the frequency distribution is somewhat skewed toward the lower intervals.
1. Determine the midpoints for each interval:
- For the interval [tex]\(40-44\)[/tex], the midpoint is [tex]\((40 + 44) / 2 = 42\)[/tex].
- For the interval [tex]\(45-49\)[/tex], the midpoint is [tex]\((45 + 49) / 2 = 47\)[/tex].
- For the interval [tex]\(50-54\)[/tex], the midpoint is [tex]\((50 + 54) / 2 = 52\)[/tex].
- For the interval [tex]\(55-59\)[/tex], the midpoint is [tex]\((55 + 59) / 2 = 57\)[/tex].
- For the interval [tex]\(60-64\)[/tex], the midpoint is [tex]\((60 + 64) / 2 = 62\)[/tex].
2. List the midpoints and their corresponding frequencies:
[tex]\[ \begin{array}{cc} \text{Midpoint} & \text{Frequency} \\ \hline 42 & 3 \\ 47 & 6 \\ 52 & 12 \\ 57 & 7 \\ 62 & 3 \\ \end{array} \][/tex]
3. Calculate the weighted sum of the midpoints:
- Multiply each midpoint by its corresponding frequency and sum the results:
[tex]\[ (42 \times 3) + (47 \times 6) + (52 \times 12) + (57 \times 7) + (62 \times 3) \][/tex]
[tex]\[ = 126 + 282 + 624 + 399 + 186 \][/tex]
[tex]\[ = 1617 \][/tex]
4. Calculate the total number of data points:
- Sum the frequencies:
[tex]\[ 3 + 6 + 12 + 7 + 3 = 31 \][/tex]
5. Find the mean of the frequency distribution:
- Divide the weighted sum of the midpoints by the total number of data points:
[tex]\[ \text{Mean} = \frac{1617}{31} \approx 52.161 \][/tex]
- Rounded to the nearest tenth:
[tex]\[ \text{Mean} \approx 52.2 \][/tex]
So, the mean of the frequency distribution is approximately [tex]\(52.2\)[/tex] degrees.
When comparing this computed mean to the actual mean of [tex]\(56.4\)[/tex] degrees, we observe that the computed mean is lower. This indicates that the frequency distribution is somewhat skewed toward the lower intervals.
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.