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The town of Shinbone, Kansas, has a population of 211,732 and experienced 47 bank robberies during the past year.

Compute the rate of bank robberies per 100,000 population.

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GinnyAnswer
Sure! To determine the rate of bank robberies per 100,000 population for the town of Shinbone, Kansas, follow these steps:

1. Understand the Components:
- The town's population is 211,732.
- The number of bank robberies in the past year is 47.

2. Set Up the Fraction:
- The fraction needs the number of bank robberies as the numerator and the population size as the denominator.
- Fraction: [tex]\( \frac{47}{211,732} \)[/tex]

3. Convert the Fraction to a Rate per 100,000 Population:
- To find out the bank robbery rate per 100,000 people, multiply the fraction by 100,000.

4. Calculate the Rate:
- Perform the following calculation: [tex]\( \left( \frac{47}{211,732} \right) \times 100,000 \)[/tex]

This will yield the bank robbery rate per 100,000 population.

5. Result:
- After completing these calculations, we find that the bank robbery rate in Shinbone, Kansas per 100,000 population is approximately 22.198.

Thus, the town of Shinbone experienced about 22.198 bank robberies per 100,000 population over the past year.
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