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Ammonium hydrogen phosphate [tex]\(\left((NH_4)_2HPO_4\right)\)[/tex], a common fertilizer, is made by reacting phosphoric acid [tex]\(\left(H_3PO_4\right)\)[/tex] with ammonia according to the following reaction:

[tex]\[ 2 NH_3 + H_3PO_4 \rightarrow (NH_4)_2HPO_4 \][/tex]

What is the ratio of [tex]\(NH_3\)[/tex] to [tex]\(H_3PO_4\)[/tex]?

[tex]\[ NH_3 : H_3PO_4 = 2 : \square \][/tex]

Sagot :

GinnyAnswer
To find the ratio of [tex]\( NH_3 \)[/tex] to [tex]\( H_3PO_4 \)[/tex] in the given reaction, we start by examining the balanced chemical equation:

[tex]\[ 2 NH_3 + H_3PO_4 \rightarrow (NH_4)_2HPO_4 \][/tex]

The coefficients in the balanced chemical equation indicate the molar ratios of the reactants and products. Here, the coefficient of [tex]\( NH_3 \)[/tex] is 2 and the coefficient of [tex]\( H_3PO_4 \)[/tex] is 1.

This means that for every 2 moles of [tex]\( NH_3 \)[/tex] used, 1 mole of [tex]\( H_3PO_4 \)[/tex] is required.

Thus, the ratio of [tex]\( NH_3 \)[/tex] to [tex]\( H_3PO_4 \)[/tex] is:

[tex]\[ NH_3 : H_3PO_4 = 2 : 1 \][/tex]

Therefore, the missing number in the ratio [tex]\( NH_3 : H_3PO_4 = 2 : \square \)[/tex] is:

[tex]\[ NH_3 : H_3PO_4 = 2 : 1 \][/tex]
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