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the length of a rectangle is 4yd more than twice the width of x the area is 336 yd^2 find the dimension

Sagot :

Answer:

length = 28 yards

width = 12 yards

Step-by-step explanation:

We can find the dimension of the rectangle with the length is 4 yd more than twice the width and its area is 336 yd² by using this formula:

[tex]\boxed{area=length\times width}[/tex]

Given that [tex]width=x[/tex], then [tex]length=(2x+4)[/tex]

[tex]area=length\times width[/tex]

[tex]336=(2x+4)(x)[/tex]

[tex]2x^2+4x-336=0[/tex]

[tex]x^2+2x-168=0[/tex]

[tex](x-12)(x+14)=0[/tex]

[tex]x=-14\ or\ 12[/tex]

Since [tex]x[/tex] (width) cannot be negative, then:

  • [tex]width=12\ yd[/tex]
  • [tex]length=2(12)+4=28\ yd[/tex]

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