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Given the transformations [tex]\( (x, y) \rightarrow (x-2, y-2) \)[/tex] and reflection over the line [tex]\( y = x \)[/tex], find the coordinates of [tex]\( P \)[/tex] if [tex]\( P' \)[/tex] is at [tex]\( (3,0) \)[/tex].

The coordinates of [tex]\( P \)[/tex] are [tex]\( \boxed{(-6, 1)} \)[/tex].


Sagot :

To find the original coordinates of point [tex]\( P \)[/tex], given that [tex]\( P' = (3, 0) \)[/tex] is the transformed point after applying a series of transformations, we need to work backward through each transformation step by step.

1. Reflection over the line [tex]\( y = x \)[/tex]:
When you reflect a point over the line [tex]\( y = x \)[/tex], the coordinates of the point are swapped. So if the image point after reflection (let's call it [tex]\( P'_{\text{reflect}} \)[/tex]) has coordinates [tex]\( (3, 0) \)[/tex], then the point before reflection (let's call it [tex]\( P_{\text{before reflect}} \)[/tex]) has coordinates [tex]\( (0, 3) \)[/tex].

2. Inverse the translation:
Next, we need to consider the translation transformation [tex]\( (x, y) \rightarrow (x-2, y-2) \)[/tex]. To find the original coordinates [tex]\( (x, y) \)[/tex], we need to reverse this translation. If [tex]\( P_{\text{translated}} = (0, 3) \)[/tex], then reversing the translation means adding 2 to each coordinate:

[tex]\[ x = 0 + 2 = 2 \][/tex]
[tex]\[ y = 3 + 2 = 5 \][/tex]

So, the original coordinates [tex]\( P \)[/tex] before any transformations are [tex]\( (2, 5) \)[/tex].

Therefore, the coordinates of [tex]\( P \)[/tex] are [tex]\( (2, 5) \)[/tex].
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