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Find the equation of a plane with center C(1, -2, 4) and radius 3.

Sagot :

It seems there might be a misunderstanding in the interpretation of the problem statement. From the information provided, we are given a center at (1, -2, 4) and a radius of 3. These values are more consistent with the parameters for defining a sphere rather than a plane.

To find the equation of the sphere with center [tex]\((1, -2, 4)\)[/tex] and radius [tex]\(3\)[/tex], we follow these steps:

1. Identify the formula for the equation of a sphere:
The general equation for a sphere centered at [tex]\((X_c, Y_c, Z_c)\)[/tex] with radius [tex]\(R\)[/tex] is given by:
[tex]\[ (x - X_c)^2 + (y - Y_c)^2 + (z - Z_c)^2 = R^2 \][/tex]

2. Substitute the given center coordinates and radius into the formula:
- Center [tex]\((X_c, Y_c, Z_c) = (1, -2, 4)\)[/tex]
- Radius [tex]\(R = 3\)[/tex]

Substituting these values into the sphere equation we get:
[tex]\[ (x - 1)^2 + (y - (-2))^2 + (z - 4)^2 = 3^2 \][/tex]

3. Simplify the radius squared:
[tex]\[ 3^2 = 9 \][/tex]

4. Write the final equation:
Therefore, the equation of the sphere is:
[tex]\[ (x - 1)^2 + (y + 2)^2 + (z - 4)^2 = 9 \][/tex]

Thus, the equation of the sphere with center at [tex]\((1, -2, 4)\)[/tex] and radius [tex]\(3\)[/tex] is:
[tex]\[ (x - 1)^2 + (y + 2)^2 + (z - 4)^2 = 9 \][/tex]