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What is the value of [tex]\(3d + 5\)[/tex] when [tex]\(d = 2\)[/tex]?

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GinnyAnswer
To find the value of the expression [tex]\(3d + 5\)[/tex] when [tex]\(d = 2\)[/tex], follow these steps:

1. Substitute the value of [tex]\(d\)[/tex] into the expression:
Given that [tex]\(d = 2\)[/tex], replace [tex]\(d\)[/tex] in the expression [tex]\(3d + 5\)[/tex] with 2.

[tex]\[ 3(2) + 5 \][/tex]

2. Perform the multiplication:
Multiply 3 by 2.

[tex]\[ 3 \times 2 = 6 \][/tex]

3. Add the constant term:
Now, add 5 to the result from the multiplication.

[tex]\[ 6 + 5 \][/tex]

4. Simplify the addition:
Perform the addition to get the final result.

[tex]\[ 6 + 5 = 11 \][/tex]

Therefore, the value of [tex]\(3d + 5\)[/tex] when [tex]\(d = 2\)[/tex] is 11.
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