Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Sure, let's break down the problem step by step.
First, we will address arranging the given numbers in ascending order of magnitude:
- The numbers to be arranged are [tex]\(\sqrt[3]{3}, \sqrt[3]{4}, \sqrt[3]{2}\)[/tex].
To solve this, we evaluate these cube roots:
1. [tex]\(\sqrt[3]{2}\)[/tex] approximately equals [tex]\(1.2599210498948732\)[/tex],
2. [tex]\(\sqrt[3]{3}\)[/tex] approximately equals [tex]\(1.4422495703074083\)[/tex],
3. [tex]\(\sqrt[3]{4}\)[/tex] approximately equals [tex]\(1.5874010519681994\)[/tex].
Now, we sort these values from smallest to largest:
- [tex]\(1.2599210498948732\)[/tex] corresponding to [tex]\(\sqrt[3]{2}\)[/tex],
- [tex]\(1.4422495703074083\)[/tex] corresponding to [tex]\(\sqrt[3]{3}\)[/tex],
- [tex]\(1.5874010519681994\)[/tex] corresponding to [tex]\(\sqrt[3]{4}\)[/tex].
Therefore, the ascending order is:
1. [tex]\(\sqrt[3]{2}\)[/tex],
2. [tex]\(\sqrt[3]{3}\)[/tex],
3. [tex]\(\sqrt[3]{4}\)[/tex].
Next, we will address arranging the given numbers in descending order of magnitude:
- The numbers to be arranged are [tex]\(\sqrt[8]{90}, \sqrt[7]{10}, \sqrt{6}\)[/tex].
To solve this, we evaluate these roots:
1. [tex]\(\sqrt{6}\)[/tex] (square root of 6) approximately equals [tex]\(2.449489742783178\)[/tex],
2. [tex]\(\sqrt[7]{10}\)[/tex] (seventh root of 10) approximately equals [tex]\(1.3894954943731377\)[/tex],
3. [tex]\(\sqrt[8]{90}\)[/tex] (eighth root of 90) approximately equals [tex]\(1.7550129025853407\)[/tex].
Now, we sort these values from largest to smallest:
- [tex]\(2.449489742783178\)[/tex] corresponding to [tex]\(\sqrt{6}\)[/tex],
- [tex]\(1.7550129025853407\)[/tex] corresponding to [tex]\(\sqrt[8]{90}\)[/tex],
- [tex]\(1.3894954943731377\)[/tex] corresponding to [tex]\(\sqrt[7]{10}\)[/tex].
Therefore, the descending order is:
1. [tex]\(\sqrt{6}\)[/tex],
2. [tex]\(\sqrt[8]{90}\)[/tex],
3. [tex]\(\sqrt[7]{10}\)[/tex].
So, summarizing:
- The ascending order for [tex]\(\sqrt[3]{3}, \sqrt[3]{4}, \sqrt[3]{2}\)[/tex] is: [tex]\(\sqrt[3]{2}, \sqrt[3]{3}, \sqrt[3]{4}\)[/tex].
- The descending order for [tex]\(\sqrt[8]{90}, \sqrt[7]{10}, \sqrt{6}\)[/tex] is: [tex]\(\sqrt{6}, \sqrt[8]{90}, \sqrt[7]{10}\)[/tex].
First, we will address arranging the given numbers in ascending order of magnitude:
- The numbers to be arranged are [tex]\(\sqrt[3]{3}, \sqrt[3]{4}, \sqrt[3]{2}\)[/tex].
To solve this, we evaluate these cube roots:
1. [tex]\(\sqrt[3]{2}\)[/tex] approximately equals [tex]\(1.2599210498948732\)[/tex],
2. [tex]\(\sqrt[3]{3}\)[/tex] approximately equals [tex]\(1.4422495703074083\)[/tex],
3. [tex]\(\sqrt[3]{4}\)[/tex] approximately equals [tex]\(1.5874010519681994\)[/tex].
Now, we sort these values from smallest to largest:
- [tex]\(1.2599210498948732\)[/tex] corresponding to [tex]\(\sqrt[3]{2}\)[/tex],
- [tex]\(1.4422495703074083\)[/tex] corresponding to [tex]\(\sqrt[3]{3}\)[/tex],
- [tex]\(1.5874010519681994\)[/tex] corresponding to [tex]\(\sqrt[3]{4}\)[/tex].
Therefore, the ascending order is:
1. [tex]\(\sqrt[3]{2}\)[/tex],
2. [tex]\(\sqrt[3]{3}\)[/tex],
3. [tex]\(\sqrt[3]{4}\)[/tex].
Next, we will address arranging the given numbers in descending order of magnitude:
- The numbers to be arranged are [tex]\(\sqrt[8]{90}, \sqrt[7]{10}, \sqrt{6}\)[/tex].
To solve this, we evaluate these roots:
1. [tex]\(\sqrt{6}\)[/tex] (square root of 6) approximately equals [tex]\(2.449489742783178\)[/tex],
2. [tex]\(\sqrt[7]{10}\)[/tex] (seventh root of 10) approximately equals [tex]\(1.3894954943731377\)[/tex],
3. [tex]\(\sqrt[8]{90}\)[/tex] (eighth root of 90) approximately equals [tex]\(1.7550129025853407\)[/tex].
Now, we sort these values from largest to smallest:
- [tex]\(2.449489742783178\)[/tex] corresponding to [tex]\(\sqrt{6}\)[/tex],
- [tex]\(1.7550129025853407\)[/tex] corresponding to [tex]\(\sqrt[8]{90}\)[/tex],
- [tex]\(1.3894954943731377\)[/tex] corresponding to [tex]\(\sqrt[7]{10}\)[/tex].
Therefore, the descending order is:
1. [tex]\(\sqrt{6}\)[/tex],
2. [tex]\(\sqrt[8]{90}\)[/tex],
3. [tex]\(\sqrt[7]{10}\)[/tex].
So, summarizing:
- The ascending order for [tex]\(\sqrt[3]{3}, \sqrt[3]{4}, \sqrt[3]{2}\)[/tex] is: [tex]\(\sqrt[3]{2}, \sqrt[3]{3}, \sqrt[3]{4}\)[/tex].
- The descending order for [tex]\(\sqrt[8]{90}, \sqrt[7]{10}, \sqrt{6}\)[/tex] is: [tex]\(\sqrt{6}, \sqrt[8]{90}, \sqrt[7]{10}\)[/tex].
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.