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Amelia truncates a positive number, [tex]\( x \)[/tex], to 1 decimal place to get another number, [tex]\( y \)[/tex].

Is it possible for [tex]\( y \)[/tex] to be larger than [tex]\( x \)[/tex]?

Write a sentence to explain your answer.

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GinnyAnswer
To determine if it is possible for the number [tex]\( y \)[/tex] to be larger than [tex]\( x \)[/tex] when [tex]\( x \)[/tex] is truncated to 1 decimal place, let's consider an example. Suppose [tex]\( x \)[/tex] is 3.456.

When truncating a number to one decimal place, we simply remove any digits beyond the first decimal place without rounding.

So, for [tex]\( x = 3.456 \)[/tex]:

1. Original number [tex]\( x \)[/tex] = 3.456
2. After truncation to one decimal place, [tex]\( y \)[/tex] = 3.4

In this example, [tex]\( y \)[/tex] after truncation is 3.4, which is clearly less than [tex]\( x \)[/tex], 3.456.

Hence, it is not possible for [tex]\( y \)[/tex] to be larger than [tex]\( x \)[/tex] when a number is truncated to 1 decimal place. Truncation always either keeps the number the same if it ends at the truncation point, or reduces the value since any digits beyond the truncation point are discarded.
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