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What is the midpoint of the line segment with endpoints (1, -6) and (-3, 4)?

A. (-1, -1)
B. (-2, -1)
C. (-2, -2)
D. (-1, -2)


Sagot :

To find the midpoint of a line segment with given endpoints, we use the midpoint formula. The midpoint [tex]\(M\)[/tex] of a line segment with endpoints [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is given by:

[tex]\[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \][/tex]

Given the endpoints [tex]\((1, -6)\)[/tex] and [tex]\((-3, 4)\)[/tex], we can find the midpoint as follows:

1. Calculate the x-coordinate of the midpoint:
[tex]\[ \text{midpoint}_x = \frac{1 + (-3)}{2} = \frac{1 - 3}{2} = \frac{-2}{2} = -1 \][/tex]

2. Calculate the y-coordinate of the midpoint:
[tex]\[ \text{midpoint}_y = \frac{-6 + 4}{2} = \frac{-6 + 4}{2} = \frac{-2}{2} = -1 \][/tex]

So, the coordinates of the midpoint are [tex]\((-1, -1)\)[/tex].

Thus, the midpoint of the line segment with endpoints [tex]\((1, -6)\)[/tex] and [tex]\((-3, 4)\)[/tex] is [tex]\(\boxed{(-1, -1)}\)[/tex].