Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Ask your questions and receive precise answers from experienced professionals across different disciplines. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Show that the language
L = {a
nb
kcnd
k : n ≥ 0,k > n}
is not regular.

Sagot :

Answer:

To show that the language L = {a

nb

kcnd

k : n ≥ 0,k > n} is not regular, we can use the pumping lemma for regular languages. Here is a proof by contradiction:

Assume that L is regular. Then, by the pumping lemma, there exists a positive integer p such that any string w in L of length at least p can be divided into three parts: w = xyz, such that |yx| < p, |y| > 0, and for all i > 0, w

(xy^i)z is also in L.

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.