Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Create a linear model for the data in the table.

[tex]\[
\begin{tabular}{|c|c|c|c|c|}
\hline
$x$ & 5 & 7 & 9 & 11 \\
\hline
$y$ & 6 & 16 & 20 & 15 \\
\hline
\end{tabular}
\][/tex]

Write a linear model for the data in the form [tex]\( y = mx + b \)[/tex].

[tex]\( y = \_\_\_ x + \_\_\_ \)[/tex]

(Type integers or decimals rounded to three decimal places as needed.)

Sagot :

GinnyAnswer
To create a linear model [tex]\( y = mx + c \)[/tex] for the data given in the table, we need to determine the slope [tex]\( m \)[/tex] and the intercept [tex]\( c \)[/tex] of the best-fit line.

The data points provided are:
- [tex]\((5, 6)\)[/tex]
- [tex]\((7, 16)\)[/tex]
- [tex]\((9, 20)\)[/tex]
- [tex]\((11, 15)\)[/tex]

Based on the given data, the calculated values for the slope [tex]\( m \)[/tex] and the intercept [tex]\( c \)[/tex] of the linear model are:
- Slope ([tex]\( m \)[/tex]): 1.550
- Intercept ([tex]\( c \)[/tex]): 1.850

Therefore, we can write the linear model for the data as:
[tex]\[ y = 1.550x + 1.850 \][/tex]

So the final linear model is:
[tex]\[ y = \boxed{1.550}x + \boxed{1.850} \][/tex]
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.