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If [tex]\( f(x) = 3x + 1 \)[/tex], then [tex]\( f(a+h) - f(a) \)[/tex] is:

A. [tex]\( h \)[/tex]

B. [tex]\( 3h \)[/tex]

C. [tex]\( 3h + 2 \)[/tex]

Sagot :

To solve for [tex]\( f(a + h) - f(a) \)[/tex] where the function [tex]\( f(x) = 3x + 1 \)[/tex], let's follow these steps:

1. Compute [tex]\( f(a + h) \)[/tex]:
[tex]\[ f(a + h) = 3(a + h) + 1 \][/tex]
Expanding this, we get:
[tex]\[ f(a + h) = 3a + 3h + 1 \][/tex]

2. Compute [tex]\( f(a) \)[/tex]:
[tex]\[ f(a) = 3a + 1 \][/tex]

3. Find the difference [tex]\( f(a + h) - f(a) \)[/tex]:
[tex]\[ f(a + h) - f(a) = (3a + 3h + 1) - (3a + 1) \][/tex]
Simplifying this expression, we notice that the [tex]\( 3a \)[/tex] and [tex]\( +1 \)[/tex] terms cancel out:
[tex]\[ f(a + h) - f(a) = 3a + 3h + 1 - 3a - 1 = 3h \][/tex]

Hence, the difference [tex]\( f(a + h) - f(a) \)[/tex] simplifies to:
[tex]\[ 3h \][/tex]

Thus, the correct answer is:
[tex]\[ \boxed{3h} \][/tex]
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