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Sagot :
We will now complete the last step step-by-step to convert the given equation into its standard form by completing the square.
Given that we have completed steps 1 through 3, we have:
[tex]\[ x^2 + 12x + 36 + y^2 + 2y + 1 = 1 + 36 + 1 \][/tex]
### Step 4: Write each trinomial as a binomial squared and simplify the right side
First, let's factor the trinomials on the left side:
[tex]\[ x^2 + 12x + 36 = (x + 6)^2 \][/tex]
[tex]\[ y^2 + 2y + 1 = (y + 1)^2 \][/tex]
So, the equation:
[tex]\[ x^2 + 12x + 36 + y^2 + 2y + 1 = 38 \][/tex]
becomes:
[tex]\[ (x + 6)^2 + (y + 1)^2 = 38 \][/tex]
Thus, the completed squares and the standard form of the given equation are:
[tex]\[ (x + 6)^2 + (y + 1)^2 = 38 \][/tex]
So, completing the square, we have:
[tex]\[ (x + 6), (y + 1), 38 \][/tex]
Therefore, the final equation in its standard form is:
[tex]\[ (x + 6)^2 + (y + 1)^2 = 38 \][/tex]
Given that we have completed steps 1 through 3, we have:
[tex]\[ x^2 + 12x + 36 + y^2 + 2y + 1 = 1 + 36 + 1 \][/tex]
### Step 4: Write each trinomial as a binomial squared and simplify the right side
First, let's factor the trinomials on the left side:
[tex]\[ x^2 + 12x + 36 = (x + 6)^2 \][/tex]
[tex]\[ y^2 + 2y + 1 = (y + 1)^2 \][/tex]
So, the equation:
[tex]\[ x^2 + 12x + 36 + y^2 + 2y + 1 = 38 \][/tex]
becomes:
[tex]\[ (x + 6)^2 + (y + 1)^2 = 38 \][/tex]
Thus, the completed squares and the standard form of the given equation are:
[tex]\[ (x + 6)^2 + (y + 1)^2 = 38 \][/tex]
So, completing the square, we have:
[tex]\[ (x + 6), (y + 1), 38 \][/tex]
Therefore, the final equation in its standard form is:
[tex]\[ (x + 6)^2 + (y + 1)^2 = 38 \][/tex]
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