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If NWA 285 was descending at 25 feet per second from an altitude of 10,000 feet to 3,000 feet while traveling at 240 knots, how many miles would the plane have traveled during the descent?

Sagot :

GinnyAnswer
To determine how many miles NWA 285 would have traveled while descending from 10,000 feet to 3,000 feet, we can follow these steps:

1. Determine the total change in altitude:
- Initial altitude: 10,000 feet
- Final altitude: 3,000 feet
- Change in altitude = 10,000 feet - 3,000 feet = 7,000 feet

2. Calculate the total time of descent:
- Descent rate: 25 feet per second
- Total descent time = Change in altitude / Descent rate
= 7,000 feet / 25 feet per second
= 280 seconds

3. Convert the speed of the plane from miles per hour to feet per second:
- Speed: 240 miles per hour
- Convert miles per hour to feet per second (1 mile = 5,280 feet, 1 hour = 3,600 seconds)
- Speed in feet per second = 240 miles per hour (5,280 feet / 3,600 seconds)
≈ 352 feet per second

4. Calculate the horizontal distance traveled during the descent:
- Horizontal distance in feet = Speed in feet per second Total descent time
= 352 feet per second * 280 seconds
= 98,560 feet

5. Convert the horizontal distance from feet to miles:
- Horizontal distance in miles = Horizontal distance in feet / 5,280 feet per mile
= 98,560 feet / 5,280 feet per mile
≈ 18.67 miles

Therefore, NWA 285 would have traveled approximately 18.67 miles horizontally while descending from an altitude of 10,000 feet to 3,000 feet.
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