Answered

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a chemist prepares a solution of copper(II) fluoride by measuring out 0.0282g of copper (II) fluoride into a 50.mL

Sagot :

Answer:

The mass concentration of copper(II) fluoride in the prepared solution is approximately 5.6 g/L.

This can be calculated by using the formula:

concentration = (mass)/volume

In this case, the mass of copper(II) fluoride is 0.0282 g and the volume of the solution is 50 mL, which is equivalent to 0.05 L.

Therefore, the mass concentration is:

(0.0282 g) / (0.05 L) = 5.6 g/L

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