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If 29cos theta = 21 find the value of 1/(sin theta - tan theta)

Sagot :

Luv2Teach

Answer:

Step-by-step explanation:

[tex]cos\theta=\frac{21}{29}[/tex]

Make a right triangle with these values in Q1. The adjacent side is 21 and the hypotenuse is 29. If we want both sin and tan, we need the opposite side:

[tex]29^2-21^2=b^2[/tex]

b = 20

[tex]\frac{1}{sin\theta-tan\theta}=\frac{1}{\frac{20}{29}-\frac{20}{21} }=\frac{1}{-\frac{160}{609} }=-\frac{609}{160}[/tex]

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