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A linear relationship is given in the table.

| [tex]\(x\)[/tex] | [tex]\(y\)[/tex] |
|------|------|
| 6 | -2 |
| 2 | 2 |
| 0 | 4 |
| -2 | 6 |

What is the slope of the relationship?

A. -2
B. -1
C. 1
D. 2

Sagot :

To determine the slope of the linear relationship given in the table, we need to use the points provided to calculate the slope. The slope ([tex]\(m\)[/tex]) between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is given by the formula:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]

Using the points from the table:

1. Calculate the slope between the points [tex]\((6, -2)\)[/tex] and [tex]\((2, 2)\)[/tex]:
[tex]\[ m_1 = \frac{2 - (-2)}{2 - 6} = \frac{2 + 2}{2 - 6} = \frac{4}{-4} = -1 \][/tex]

2. Calculate the slope between the points [tex]\((2, 2)\)[/tex] and [tex]\((0, 4)\)[/tex]:
[tex]\[ m_2 = \frac{4 - 2}{0 - 2} = \frac{4 - 2}{-2} = \frac{2}{-2} = -1 \][/tex]

3. Calculate the slope between the points [tex]\((0, 4)\)[/tex] and [tex]\((-2, 6)\)[/tex]:
[tex]\[ m_3 = \frac{6 - 4}{-2 - 0} = \frac{6 - 4}{-2} = \frac{2}{-2} = -1 \][/tex]

Since the slopes between all points are the same ([tex]\(m_1 = m_2 = m_3 = -1\)[/tex]), we can confirm that the slope of the linear relationship is consistent.

Therefore, the slope of the relationship given in the table is:
[tex]\[ \boxed{-1} \][/tex]