Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To solve the problem of finding the probability that an individual had between \[tex]$0.71 and \$[/tex]0.92, given a normal distribution with [tex]\(\mu = 1\)[/tex] and [tex]\(\sigma = 1\)[/tex], we'll proceed as follows:
### Step-by-Step Solution
1. Determine the z-scores:
The z-score for a value [tex]\(x\)[/tex] in a normal distribution is calculated using the formula:
[tex]\[ z = \frac{x - \mu}{\sigma} \][/tex]
For the lower bound [tex]\( x = 0.71 \)[/tex]:
[tex]\[ z_{\text{lower}} = \frac{0.71 - 1}{1} = -0.29 \][/tex]
For the upper bound [tex]\( x = 0.92 \)[/tex]:
[tex]\[ z_{\text{upper}} = \frac{0.92 - 1}{1} = -0.08 \][/tex]
2. Find the cumulative probabilities:
Using the standard normal distribution table (or a cumulative distribution function, CDF):
- The cumulative probability [tex]\( P(Z < z_{\text{lower}}) \)[/tex] for [tex]\( z_{\text{lower}} = -0.29 \)[/tex] is approximately 0.3859.
- The cumulative probability [tex]\( P(Z < z_{\text{upper}}) \)[/tex] for [tex]\( z_{\text{upper}} = -0.08 \)[/tex] is approximately 0.4681.
3. Calculate the probability between the two z-scores:
To find the probability that an individual has between [tex]$0.71 and $[/tex]0.92, we subtract the cumulative probabilities:
[tex]\[ P(0.71 < X < 0.92) = P(Z < z_{\text{upper}}) - P(Z < z_{\text{lower}}) \][/tex]
[tex]\[ P(0.71 < X < 0.92) = 0.4681 - 0.3859 = 0.0822 \][/tex]
Thus, the probability that an individual had between \[tex]$0.71 and \$[/tex]0.92 is 0.0822 (rounded to four decimal places).
### Graphing the Situation
To visualize this, you would draw the standard normal distribution curve, which is bell-shaped and centered at [tex]\(z = 0\)[/tex].
- Shade the area between [tex]\(z = -0.29\)[/tex] and [tex]\(z = -0.08\)[/tex].
Let's break this down:
1. Draw a horizontal axis (z-axis) and a vertical axis (probability density).
2. Sketch the bell-shaped curve of the standard normal distribution.
3. Mark [tex]\(z = -0.29\)[/tex] and [tex]\(z = -0.08\)[/tex] on the z-axis.
4. Shade the area under the curve between these two z-scores.
This shaded region represents the probability that an individual had between \[tex]$0.71 and \$[/tex]0.92, which is 0.0822.
### Step-by-Step Solution
1. Determine the z-scores:
The z-score for a value [tex]\(x\)[/tex] in a normal distribution is calculated using the formula:
[tex]\[ z = \frac{x - \mu}{\sigma} \][/tex]
For the lower bound [tex]\( x = 0.71 \)[/tex]:
[tex]\[ z_{\text{lower}} = \frac{0.71 - 1}{1} = -0.29 \][/tex]
For the upper bound [tex]\( x = 0.92 \)[/tex]:
[tex]\[ z_{\text{upper}} = \frac{0.92 - 1}{1} = -0.08 \][/tex]
2. Find the cumulative probabilities:
Using the standard normal distribution table (or a cumulative distribution function, CDF):
- The cumulative probability [tex]\( P(Z < z_{\text{lower}}) \)[/tex] for [tex]\( z_{\text{lower}} = -0.29 \)[/tex] is approximately 0.3859.
- The cumulative probability [tex]\( P(Z < z_{\text{upper}}) \)[/tex] for [tex]\( z_{\text{upper}} = -0.08 \)[/tex] is approximately 0.4681.
3. Calculate the probability between the two z-scores:
To find the probability that an individual has between [tex]$0.71 and $[/tex]0.92, we subtract the cumulative probabilities:
[tex]\[ P(0.71 < X < 0.92) = P(Z < z_{\text{upper}}) - P(Z < z_{\text{lower}}) \][/tex]
[tex]\[ P(0.71 < X < 0.92) = 0.4681 - 0.3859 = 0.0822 \][/tex]
Thus, the probability that an individual had between \[tex]$0.71 and \$[/tex]0.92 is 0.0822 (rounded to four decimal places).
### Graphing the Situation
To visualize this, you would draw the standard normal distribution curve, which is bell-shaped and centered at [tex]\(z = 0\)[/tex].
- Shade the area between [tex]\(z = -0.29\)[/tex] and [tex]\(z = -0.08\)[/tex].
Let's break this down:
1. Draw a horizontal axis (z-axis) and a vertical axis (probability density).
2. Sketch the bell-shaped curve of the standard normal distribution.
3. Mark [tex]\(z = -0.29\)[/tex] and [tex]\(z = -0.08\)[/tex] on the z-axis.
4. Shade the area under the curve between these two z-scores.
This shaded region represents the probability that an individual had between \[tex]$0.71 and \$[/tex]0.92, which is 0.0822.
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.