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What is the pH of a 0.1 M KOH solution?

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GinnyAnswer
To determine the pH of a 0.1 M KOH solution, let's go through the problem step-by-step.

1. Identify the nature of the solute:
Potassium hydroxide (KOH) is a strong base which completely dissociates in water. This means that for every mole of KOH dissolved, it produces one mole of hydroxide ions (OH⁻).

2. Determine the concentration of hydroxide ions (OH⁻):
Since the concentration of the KOH solution is 0.1 M and it fully dissociates in water, the concentration of hydroxide ions (OH⁻) will also be 0.1 M.

3. Calculate the pOH of the solution:
The pOH is calculated using the formula:
[tex]\[ \text{pOH} = -\log[\text{OH}^-] \][/tex]
Plugging in the concentration of hydroxide ions:
[tex]\[ \text{pOH} = -\log[0.1] = 1.0 \][/tex]

4. Determine the pH using the relationship between pH and pOH:
The relationship between pH and pOH is given by:
[tex]\[ \text{pH} + \text{pOH} = 14 \][/tex]
Knowing the pOH is 1.0, we can find the pH:
[tex]\[ \text{pH} = 14 - \text{pOH} = 14 - 1.0 = 13.0 \][/tex]

Therefore, the pH of a 0.1 M KOH solution is 13.0.
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