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If a [tex]\( 45^\circ-45^\circ-90^\circ \)[/tex] triangle has a hypotenuse length of [tex]\( 7 \sqrt{2} \)[/tex], what is the length of each leg of the triangle?

A. [tex]\( 7 \sqrt{2} \)[/tex]
B. 7
C. [tex]\( \sqrt{2} \)[/tex]
D. 2


Sagot :

To find the length of each leg in a [tex]$45^\circ-45^\circ-90^\circ$[/tex] triangle with a given hypotenuse of [tex]\(7\sqrt{2}\)[/tex], we can take advantage of the properties specific to this type of triangle. In a [tex]$45^\circ-45^\circ-90^\circ$[/tex] triangle, the lengths of the legs are equal, and the relationship between the legs and the hypotenuse is given by the formula:

[tex]\[ \text{Hypotenuse} = \text{Leg} \times \sqrt{2} \][/tex]

Given that:
[tex]\[ \text{Hypotenuse} = 7\sqrt{2} \][/tex]

To solve for one leg length, we rearrange the formula:

[tex]\[ \text{Leg} = \frac{\text{Hypotenuse}}{\sqrt{2}} \][/tex]

Substituting the given hypotenuse:

[tex]\[ \text{Leg} = \frac{7\sqrt{2}}{\sqrt{2}} \][/tex]

Now, simplifying the fraction:

[tex]\[ \text{Leg} = 7 \][/tex]

Therefore, the length of each leg of the triangle is:

[tex]\[ \boxed{7} \][/tex]