To find the mass of the piece of mahogany wood, we need to use the formula for mass, which is given by:
[tex]\[ \text{mass} = \text{density} \times \text{volume} \][/tex]
Here, the density ([tex]\( \rho \)[/tex]) of the mahogany wood is [tex]\( 0.71 \, \text{g/cm}^3 \)[/tex] and the volume ([tex]\( V \)[/tex]) is [tex]\( 1728 \, \text{cm}^3 \)[/tex].
1. Write down the given density and volume:
[tex]\[ \text{density} = 0.71 \, \text{g/cm}^3 \][/tex]
[tex]\[ \text{volume} = 1728 \, \text{cm}^3 \][/tex]
2. Substitute these values into the mass formula:
[tex]\[ \text{mass} = 0.71 \, \text{g/cm}^3 \times 1728 \, \text{cm}^3 \][/tex]
3. Perform the multiplication:
[tex]\[ \text{mass} = 0.71 \times 1728 \][/tex]
4. The result of this multiplication is [tex]\( 1226.8799999999999 \, \text{g} \)[/tex].
Therefore, the mass of the piece of mahogany wood is [tex]\( 1226.8799999999999 \, \text{g} \)[/tex].
