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### Chemical Reactions

#### Reaction 1:
[tex]$
\text{K}_2\text{SO}_4\text{(aq)} + \text{Ba(NO}_3\text{)}_2\text{(aq)} \rightarrow 2 \text{KNO}_3\text{(aq)} + \text{BaSO}_4\text{(s)}
$[/tex]

\begin{tabular}{|l|l|l|}
\hline
Reactivos & Elementos & Productos \\
\hline
& & \\
\hline
& & \\
\hline
\end{tabular}

#### Reaction 2:
[tex]$
\text{FeCl}_2\text{(aq)} + \text{Ba}_3(\text{PO}_4)_2\text{(aq)} \rightarrow \text{Fe}_3(\text{PO}_4)_2\text{(s)} + \text{NaCl}\text{(aq)}
$[/tex]

\begin{tabular}{|l|l|l|}
\hline
Reactivos & Elementos & Productos \\
\hline
& & \\
\hline
\end{tabular}

Sagot :

GinnyAnswer
Sure, let's break down each reaction you have provided and categorize the reactants and products.

### 1. Reaction:
[tex]\[ K_2SO_4(aq) + Ba(NO_3)_2(aq) \rightarrow 2KNO_3(aq) + BaSO_4(s) \][/tex]

In this reaction, we have:

#### Reactants:
- [tex]\( K_2SO_4 \)[/tex] (Potassium sulfate) in aqueous form (aq)
- [tex]\( Ba(NO_3)_2 \)[/tex] (Barium nitrate) in aqueous form (aq)

#### Products:
- [tex]\( 2KNO_3 \)[/tex] (Potassium nitrate) in aqueous form (aq)
- [tex]\( BaSO_4 \)[/tex] (Barium sulfate) in solid form (s)

### 2. Reaction:
[tex]\[ FeCl_2(aq) + Ba_3(PO_4)_2(aq) \rightarrow Fe_3(PO_4)_2(s) + NaCl(aq) \][/tex]

This reaction has a mistake: the product [tex]\(NaCl\)[/tex] should actually be [tex]\(FeCl_3\)[/tex] to balance the equation correctly. Also, the correct formula for [tex]\(Ba_3(PO_4)_2\)[/tex] should be [tex]\(Fe_3(PO_4)_2\)[/tex].

Considering the corrected reaction:
[tex]\[ 3FeCl_2(aq) + 2Ba_3(PO_4)_2(aq) \rightarrow Fe_3(PO_4)_2(s) + 6BaCl_2(aq) \][/tex]

In this reaction, we have:

#### Reactants:
- [tex]\( 3FeCl_2 \)[/tex] (Iron(II) chloride) in aqueous form (aq)
- [tex]\( 2Ba_3(PO_4)_2 \)[/tex] (Barium phosphate) in aqueous form (aq)

#### Products:
- [tex]\( Fe_3(PO_4)_2 \)[/tex] (Iron(II) phosphate) in solid form (s)
- [tex]\( 6BaCl_2 \)[/tex] (Barium chloride) in aqueous form (aq)

### Tables

#### 1. First Reaction:

[tex]\[ \begin{array}{|c|c|c|} \hline \text{Reactants} & \text{Element} & \text{Products} \\ \hline K_2SO_4(aq) & K & 2KNO_3(aq) \\ Ba(NO_3)_2(aq) & N & BaSO_4(s) \\ & O & \\ & S & \\ & Ba & \\ \hline \end{array} \][/tex]

#### 2. Second Reaction:

[tex]\[ \begin{array}{|c|c|c|} \hline \text{Reactants} & \text{Element} & \text{Products} \\ \hline 3FeCl_2(aq) & Fe & Fe_3(PO_4)_2(s) \\ 2Ba_3(PO_4)_2(aq) & Cl & 6BaCl_2(aq) \\ & P & \\ & O & \\ & Ba & \\ \hline \end{array} \][/tex]

These pairwise balanced reactions address both the reactants and products, categorizing them accordingly based on their forms and the elements they contain.
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